2020-02-19, Wednesday
Vector Bundle
Definition : A vector bundle is a quadruple (E,π,M,F), such that
E,M are smooth manifolds
π:E→M is a surjective submersion. For each
U⊂M, we set
E∣U:=π−1(U).
F is a vector space of rank
n over
R.
there exists a trivializing cover, ie. an open cover
U of
M, and for every
U∈U a diffeomorphism
ΨU:E∣U→U×F,v↦(p=π(v),ΦpU(v))
ΦpU:Ep→F is a diffeomorphism for any
p∈U.
If
U,V∈U are two trivializing neighborhoods with non-empty overlap
U∩V, then, the map
ΦVU(p):ΦpV∘(ΦpU)−1:F→F is a linear isomorphism. And moreover, the map
p↦ΦVU(p)∈GL(n,R) is smooth (i.e. each entry of hte matrix is a smooth function of
p)
Given a smooth manifold M, and fiber F=Rn, how to specify the data of a vector bundle? We just need to specify a cover U and some gluing data: gαβ=gα←β:Uα∩Uβ→Aut(F)=GL(R,n) for any Uα,Uβ∈U, that satisfies the tricycle condition
gαβ∘gβα=1F over
Uα∩Uβ
gαβ∘gβγ∘gγα=1F over
Uα∩Uβ∩Uγ.
Example of Vector Bundles
E(n,k)→Gr(n,k) tautological bundle over the Grassmannian.
O(−1)→CP(1).
Operations on Vector Bundles
Direct Sum, Tensor Product, Hom.
Cotangent Bundle
Some linear algebra first. Let V be a finite dimensional vector space over R
Dual vector space of V is the vector space of linear function on V, denoted as V∗.
If V is a basis {E1,⋯,En}, then there is a basis basis {ϵi} of V∗, called dual basis to {Ei}, satisfying ϵi(Ej)=δji.
Given a basis for V and corresponding dual basis as above, then a vector v∈V and a covector ω∈V∗ can be written as
v=i∑viEi,ω=j∑ωjϵj
The canonical pairing (ω,v)=ω(v) can be written as
(ω,v)=i∑ωivi.
If f:V→W is a linear map, then there is a dual map f∗:V∗→W∗, given by
f(φ)(w)=φ(f(w)),w∈W,φ∈V∗.
Now, let M be a smooth manifold, p∈M, TpM its tangent space over p. We define the cotangent space at p to be Tp∗M:=(TpM)∗.
Given a coordinate system near p, (U,(x1,⋯,xn)), we have basis for TpM as {∂i∣p=∂xi∂∣p. The dual basis of {∂i}∣p is denoted as {dxi}∣p. Hence, a covector ω at p can be written as
ω=∑iωidxi∣p
Exercise: figure out the transformation rule for the coefficients ωI if we change coordinates.
Recall how we define smooth vector field over M: it is an assignment p↦X(p)∈TpM for p∈M, such that if we write it in coordinate patch (U,(xi)), we have
X(p)=i∑X(p)i∂i
where X(p)i:U→R are smooth functions.
Simiarly, we define smooth covector fields over M as an assignment p↦ω(p)∈Tp∗M, such that in coordinates we have
ω(p)=i∑ω(p)idxi
where ω(p)i are smooth.
Prop : The cotangent bundle T∗M=⊔pTp∗M is a vector bundle over M.
Given a differential 1-form, we can do line integral.
A differential 1-form is closed, if the value of the line integral is invariant under isotopy that fixes the end-points.
A differential 1-form λ is exact, if there exists a function f, such that df=λ. We say f is a primitive of λ.
Over a unit ball (or more generally, connected space with trivial π1), any closed 1-form is exact. We can find a primitive of λ, by fixing a point p0 in the space, and define f(p)=∫p0pλ.