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math104-s21:hw11

HW 11

1. Let f:RRf: \R \to \R be a differentiable function. Assume that ff is convex, namely for any x,yRx, y \in \R and any t[0,1]t \in [0,1], we have tf(x)+(1t)f(y)f(tx+(1t)y). tf(x) + (1-t) f(y) \geq f(t x + (1-t) y). Prove that f(x)f'(x) is monotonously increasing.

2. Let f:(0,)Rf: (0, \infty) \to \R be a twice differentiable function. Suppose ff'' is bounded, and f(x)0f(x) \to 0 as xx \to \infty. Show that f(x)0f'(x) \to 0 as xx \to \infty.

Hint: Use Taylor Theorem, prove that for any x>0,h>0x>0, h>0, we have f(x+h)f(x)h=f(x)+(h/2)f(ξ) \frac{f(x+h) - f(x)}{h} = f'(x) + (h/2) f“(\xi) for some ξ(x,x+h)\xi \in (x, x+h).

3. Let f:RRf: \R \to \R be a continuous function, such that f(x)f'(x) exists for all x0x \neq 0. If we know that limx0f(x)=5\lim_{x \to 0} f'(x)=5, can we conclude that f(0)=5f'(0)=5? Justify your result.

4. Given an example of real bounded function ff on [0,1][0,1] that is not Riemann integrable. Hint: ff is not continuous on [0,1][0,1]. Show that U(f)L(f)U(f) \neq L(f).

5. (Free discussion problem, no points taken). Let f:[0,1]Rf: [0,1] \to \R be a real bounded function. Assume f(x)0f(x) \geq 0 and ff is Riemann integrable. Here is a candidate that measures the area under the graph of ff:

  • For each positive integer nn, let N(n)N(n) be the number of points (x,y)R2(x,y) \in \R^2, such that x,yZ/2nx, y \in \Z / 2^n, and x[0,1],0yf(x)x \in [0,1], 0 \leq y \leq f(x). Namely, we count how many points in the 2d mesh with spacing 2n2^{-n} falls within the area under the curve y=f(x)y=f(x).
  • Let A(n)=22nN(n)A(n) = 2^{-2n} N(n). Since the area of a 2n×2n2^{-n} \times 2^{-n} square is 22n2^{-2n}.

Is it true that limnA(n)=01f(x)dx? \lim_{n \to \infty} A(n) = \int_0^1 f(x)dx ? To get started, you may assume that ff is continuous (we will see next week that continuous functions are Riemann integrable).

math104-s21/hw11.txt · Last modified: 2022/01/11 10:57 by pzhou