1. Let f:R→R be a differentiable function. Assume that f is convex, namely for any x,y∈R and any t∈[0,1], we have
tf(x)+(1−t)f(y)≥f(tx+(1−t)y).
Prove that f′(x) is monotonously increasing.
2. Let f:(0,∞)→R be a twice differentiable function. Suppose f'' is bounded, and f(x)→0 as x→∞. Show that f′(x)→0 as x→∞.
Hint: Use Taylor Theorem, prove that for any x>0,h>0, we have
hf(x+h)−f(x)=f′(x)+(h/2)f“(ξ)
for some ξ∈(x,x+h).
3. Let f:R→R be a continuous function, such that f′(x) exists for all x=0. If we know that limx→0f′(x)=5, can we conclude that f′(0)=5? Justify your result.
4. Given an example of real bounded function f on [0,1] that is not Riemann integrable. Hint: f is not continuous on [0,1]. Show that U(f)=L(f).
5. (Free discussion problem, no points taken). Let f:[0,1]→R be a real bounded function. Assume f(x)≥0 and f is Riemann integrable. Here is a candidate that measures the area under the graph of f:
For each positive integer
n, let
N(n) be the number of points
(x,y)∈R2, such that
x,y∈Z/2n, and
x∈[0,1],0≤y≤f(x). Namely, we count how many points in the 2d mesh with spacing
2−n falls within the area under the curve
y=f(x).
Let
A(n)=2−2nN(n). Since the area of a
2−n×2−n square is
2−2n.
Is it true that
n→∞limA(n)=∫01f(x)dx?
To get started, you may assume that f is continuous (we will see next week that continuous functions are Riemann integrable).