All vector spaces come equipped with a preferred inner product.
All vector spaces come equipped with a preferred basis.
If v∈V is an element in a vector space V, then it determines a dual element v∗∈V∗.
Let P be the vector space of smooth R-valued function on [0,1]. For example, f(x)=x2−2, is an element in P, or f(x)=x+11. Then, the function Φ:P→R, defined by sending f(x)∈P to ∫01x2f(x)dx is a linear function on P.
2. Area
Consider the vector space R2. Let v1=(1,1),v2=(0,2). Let P(v1,v2) denote the area of the parallelogram (skewed rectangle) generated by v1,v2. P(v1,v2)=?
From the above computation, can you deduce P(v1+3v2,v2)=? which formula did you use?
How about P(av1+bv2,cv1+dv2)=?
3. Metric tensor. Let V be a 2-dim vector space with metric tensor g. Let e1,e2 be a basis of V. Suppose we know that
g(e1,e1)=3,g(e1,e2)=1,g(e2,e2)=2
Answer the following question, recall that ∥v∥2=g(v,v).
∥e1∥=?, ∥e2∥=?
∥e1+e2∥=?
∥e1−2e2∥=?
P(e1,e2)=?
Can you find two vectors v1,v2∈R2, such that v1,v2 has the same properties as e1,e2?
4. Let V=R2 be the Euclidean vector space of 2-dim, and v,w be two vectors in it. Suppose we know that
g(v,v)=1,g(w,w)=4,g(v,w)=2
Can you deduce that v and w are collinear? (i.e. parallel? )
What if V is n-dimensional, does the above conclusion still holds?
math121b/ex3.1581200235.txt.gz · Last modified: 2020/02/08 14:17 by pzhou