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math121a-f23:september_6_wednesday [2023/09/05 11:12]
pzhou
math121a-f23:september_6_wednesday [2023/09/07 01:10] (current)
pzhou [post lecture note]
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 (optional) other weird "numbers"? (if you walk like a number, talk like a number, operate like a number, I will call you a number!) The notion of a 'field' (optional) other weird "numbers"? (if you walk like a number, talk like a number, operate like a number, I will call you a number!) The notion of a 'field'
 +
 +
 +===== post lecture note =====
 +
 +Roughly speaking, a 'ring' is a set whose elements can do addition and multiplication (among) themselves. Example: Z\Z, polynomial. (to be precise, we talk about commutative multiplication, that satisfies xy=yxx \cdot y=y\cdot x. matrix multiplication may not be commutative.)
 +
 +A 'field', is a ring where any nonzero element has a multiplicative inverse. Z\Z is not a field. Q\Q, R\R, C\C are field. 
 +
 +\gdef\F{\mathbb F}
 +
 +We talked about finite field. Given a prime number pp, we define Fp=Z/pZ\F_p = \Z / p\Z, This notation may reminds you of the quotient vector space V/WV/W, indeed, Z/pZ\Z / p \Z is the set of equivalence class, where we say two integers n1,n2n_1, n_2 are equivalent (and write n1n2(modp)n_1 \equiv n_2 (mod p)), if n1n2pZn_1 - n_2 \in p \Z, i.e. the difference is a multiple of pp. In class, we set p=7p=7, and we say 18(mod7)1 \equiv 8 (mod 7). If we use [n]=n+pZ[n] = n + p \Z the equivalence class that nn belongs to, then we write [1]=[8][1]=[8].  
 +F7={[0],[1],,[6]}\F_7 = \{ [0], [1], \cdots, [6]\} 
 +We have arithematics like
 +[a]+[b]=[a+b],[a][b]=[ab]. [a] + [b] = [a+b], \quad [a] \cdot [b] = [ab].
 +For example, [2][4]=[8]=[1][2] \cdot [4] = [8] = [1]. (When there is no danger of confusion, we just write nn for [n][n])
 +
 +Question (optional): \\
 +1. Can you write down how F5\F_5 behave? For example, what is [2]+[4]=?[2] + [4] = ? What is who multiply [3][3] equasl [1][1]
 +
 +2. 'finite field version of complex number'. Take KK be a field. We consider K[1]:=K[x]/(x2+1)={a+bxa,bK,x2=1}K[\sqrt{-1}] := K[x] / (x^2+1) = \{a + b x \mid a, b \in K, x^2 = -1\}. Is this always a field? Namely, can you always define 1/(a+bx)1/(a+bx)? We see that for K=RK = \R, this works, 1/(a+bx)=(abx)/(a2+b2)1/(a+bx) = (a-bx) / (a^2 + b^2). Does the inverse always exist for K[1]K[\sqrt{-1}]? Try K=Q, F5, F7K = \Q,  \F_5,  \F_7, see if you can find some pattern. 
 +
 +3. In class, we also talked about, can you define 'super complex number', that instead of using two real numbers a,ba,b to represent a complex number a+bia + b i, but three real numbers? For example, we can try 
 + \R[x]/(x^3-1) = \{ a+b x + c x^2 \mid a,b,c \in \R,  x^3=1 \}
 +can you define multiplication on it? (1+x+x2)(2+x)=? ( 1+ x + x^2) (2 + x) = ?
 +
 +Does every nonzero element has a (multiplicative) inverse? For example, xx has inverse, 
 +1/x=x2. 1/x = x^2.
 +x+1x+1 has inverse, we have 
 +11+x=1x+x2(1+x)(1x+x2)=1x+x21+x3=1x+x22. \frac{1}{1+x} = \frac{1-x+x^2}{(1+x)(1-x+x^2)} = \frac{1-x+x^2}{1+x^3} = \frac{1-x+x^2}{2}.
 +Does x1x-1 has inverse? 
 +
 +-------
 +
 +you may ask:  why we care about other 'field'? I am happy with C\C and R\R. I don't have a good answer for that, maybe you will find some application some day. 
 +
 +==== Exercise ====
 +(part of homework)
 +Read Boas Ch2, section 1 - 9,  find 5 interesting problems there and do it. (copy down the problem, so the grader / reader know which one you are doing). 
 +
 +
 +
 +
 +
  
  
math121a-f23/september_6_wednesday.1693937550.txt.gz · Last modified: 2023/09/05 11:12 by pzhou