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math105-s22:notes:lecture_12 [2022/02/23 23:58] pzhou [Pugh 6.8: Vitali Covering] |
math105-s22:notes:lecture_12 [2022/02/25 00:35] (current) pzhou |
∫F+(x)dx=∫F−(x)dx | ∫F+(x)dx=∫F−(x)dx |
hence F+(x)=F−(x) for almost all x. Thus, for a.e. x, we have $\uint f(x,y) dy = \lint f(x,y) dy$, thus ∫f(x,y)dy exists for a.e. x. | hence F+(x)=F−(x) for almost all x. Thus, for a.e. x, we have $\uint f(x,y) dy = \lint f(x,y) dy$, thus ∫f(x,y)dy exists for a.e. x. |
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| ==== A Lemma ==== |
| Suppose A is measurable, and B⊂A any subset, with Bc=A\B. Then |
| m(A)=m∗(B)+m∗(Bc) |
| Proof: |
| m∗(B)=inf{m(C)∣A⊃C⊃B,Cmeasurable}=inf{m(A)−m(Cc)∣A⊃C⊃B,Cmeasurable} |
| =m(A)−sup{m(Cc)∣A⊃C⊃B,Cmeasurable}=m(A)−sup{m(Cc)∣Cc⊂Bc,Ccmeasurable}=m(A)−m∗(Bc) |
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===== Pugh 6.8: Vitali Covering ===== | ===== Pugh 6.8: Vitali Covering ===== |