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Title: intersection of embedded closed sets Post by MonicaMath on Sep 17th, 2009, 11:55am Hi, I need to prove that? if {A_k}, k=1,..., infinity, is a collection of nonempty embedded closed sets of real numbers in decreasing order with A_j is bounded for one j, then : the intersection is nonempty ?? |
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Title: Re: intersection of embedded closed sets Post by Eigenray on Sep 17th, 2009, 6:12pm Are you familiar with the open cover definition of compactness? If the intersection were empty, we would have Aj = http://www.ocf.berkeley.edu/~wwu/YaBBImages/symbols/cup.gifk>j Uk, where Uk = Aj \ Ak is open in Aj. Since Aj is compact, this open cover has a finite subcover. But the Uk are nested increasing, so we must have Aj = Uk for some k, meaning Ak is empty, a contradiction. There is a more general version [link=http://planetmath.org/?op=getobj&from=objects&id=4181]here[/link]. |
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