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Title: Gaussian Integral Using Laplace Transforms Post by william wu on Apr 9th, 2004, 10:44pm Many are familiar with the trick of evaluating the Gaussian integral by multiplying the integral with a copy of itself, squarerooting, and converting to polar coordinates. This problem demonstrates a neat way of evaluating the integral using Laplace Transforms. Use the hidden steps/hints below as necessary: Step 1: [hide]Define a function f(t) = [int]0 to +inf exp(-tx2). Consider L[f(t)].[/hide] Step 2: [hide]Use the result L[1/(sqrt(pi*t)] = 1/sqrt(s).[/hide] |
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Title: Re: Gaussian Integral Using Laplace Transforms Post by Eigenray on Dec 10th, 2005, 3:37pm But step 2 is equivalent to what you're trying to show! L[1/sqrt(pi t)](s) = [int] 1/sqrt(pi t) e-st dt substituting st=x2, dt = 2x/s dx, = [int] 1/sqrt(pi x2/s) e-x^2 2x/s dx = 2/sqrt(pi s) [int] e-x^2 dx. You could also prove it using the fact that g(x)=e-pi x^2 is its own Fourier transform ... |
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