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Title: Nine Points on a Sphere Post by James Fingas on Oct 2nd, 2002, 6:46am Show how to distribute nine points around the surface of a sphere in such a way that each point is equidistant from its four nearest neighbors. // modified post to include problem statement at top - willywutang 5/21/2008 The solution to this is quite beautiful. It's like the "trees for Willywutang" question, where you just sort of stumble onto the solution. Here's a hint: The ratio of point-distance to sphere radius is 4*sqrt(6) : 7 + sqrt(2) ... ;D I'd also like to say that I have found distributions for the following numbers of points on a sphere (each equidistant from 4 neighbours): 6, 8, 10, 12, ... 9, 15, 21, ... There seems to be no possible solution for 5 or 7 points, and I'm working on 11... There are also a few distributions for 5 neighbours, but it's a MUCH harder problem in general. |
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