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Title: Roots of a polynomial in a finite field... Post by Michael Dagg on Aug 5th, 2015, 7:54pm Let Z_n be the ring of integers modulo n > 6. What is the smallest n for which the quadratic polynomial x^2 - 5x + 6 has four distinct roots? |
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Title: Re: Roots of a polynomial in a finite field... Post by towr on Aug 5th, 2015, 11:24pm by trial an error [hide]n=10, with roots x=2,3,7,8[/hide] |
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Title: Re: Roots of a polynomial in a finite field... Post by 0.999... on Aug 6th, 2015, 6:44pm Nice to see you around, Michael Dagg. So we start with the factorization (x-3)(x-2), and note that there is a one-to-one correspondence between the roots of the provided polynomial and the roots of [hide]x(x+1)[/hide], when n>6. The easiest case to consider is when n=2ep, where p is an odd prime. Here, we have 4 roots if and only if [hide]e>0, because by the Chinese Remainder Theorem there is a unique x such that x=-1(mod p) and x=0(mod 2e). Similarly, there is a unique x satisfying x=1(mod p) and x=0(mod 2e).[/hide] This is enough to resolve the problem as stated, but why not try for a classification of all n for which there are 4 roots. The stumbling block is that n may take the form 2em, and there may (could potentially) exist [hide](exactly 2 distinct) factorizations of m as k1k2 such that 2ek1+/-1=k2[/hide] and it seems to be challenging to determine precisely when this occurs. |
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