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Title: Integer triangle with 120 degrees Post by Christine on Apr 23rd, 2013, 10:35am This type of triangle can be generated by a = m2 - n2 b = 2mn + n2 c = m2 + mn + n2 we note a2 + ab + b2 = c2 If m = 2, n = 1 ---> a = 3, b = 5, c = 7 the smallest triangle with an angle of 120 degrees having all 3 sides with prime numbers. Is it the only triangle with the three sides being prime numbers? If yes, how to prove it? |
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Title: Re: Integer triangle with 120 degrees Post by towr on Apr 23rd, 2013, 10:41am [hide]Well, n has to be 1, otherwise b can't be prime (n divides 2mn + n^2). And m-n has to be 1, because otherwise a isn't prime (m-n divides m^2-n^2). So therefore m=2, n=1 is the only solution with prime numbers. Provided all such triangles can be generated in this way.[/hide] |
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Title: Re: Integer triangle with 120 degrees Post by Christine on Apr 23rd, 2013, 11:13am on 04/23/13 at 10:41:10, towr wrote:
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