|
||
Title: Representing 1 without 1's in non-integer bases. Post by towr on Mar 15th, 2010, 6:07am Can you find any real, non-integer number r, such that there exists a sequence of digits di for which \sum i=0inf di*r-i = 1 0 <= di < r and di =/= 1 (With \pi I got to 0.3003333303 2002233032 0032030320 0203322202 0003203 before it broke down.) |
||
Title: Re: Representing 1 without 1's in non-integer base Post by SMQ on Mar 15th, 2010, 6:48am Sure: just use [hide]the trick for converting repeating decimals to rationals[/hide] in reverse. e.g. [hide]0.232323...b = 1 23.2323...b = b2 23.2323...b - 0.232323...b = 23b = b2 - 1 2b + 3 = b2 - 1 b2 - 2b - 4 = 0 b = 1 +/- sqrt(5) so 0.232323... = 1 in base 2phi. [/hide] --SMQ |
||
Title: Re: Representing 1 without 1's in non-integer base Post by towr on Mar 15th, 2010, 6:58am Nice work. I should have thought of that. How about in a non-algebraic base? |
||
Powered by YaBB 1 Gold - SP 1.4! Forum software copyright © 2000-2004 Yet another Bulletin Board |