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Title: Subtract The Expressions, Get 1 Post by K Sengupta on Jun 25th, 2008, 8:45am Determine all possible triplet(s) (P, Q, R) of positive integers, that satisfy this equation: (P+2)R+1 - (P+1)Q+1 = 1 |
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Title: Re: Subtract The Expressions, Get 1 Post by TenaliRaman on Jun 30th, 2008, 1:11pm Well, it may be futile, but my working so far has given me, Q > R >= (2Q - 1) / 3 P = ((R+1) / (Q - R)) - 1 No, it doesn't mean that if P,Q,R satisfy these requirements, they are the solution. On the contrary, if they are the solution to the above system, they would satisfy the above equations :( (Sad, I know). I am trying to get some headway with this, but so far all efforts were in vain. Just posted it to see if anyone else can make any sense of it. -- AI |
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Title: Re: Subtract The Expressions, Get 1 Post by towr on Jun 30th, 2008, 1:37pm [hide]"Catalan's conjecture (now a theorem) is that 1 occurs just once as a difference [between powers>2 of integers m], between 8 and 9". So (1,2,1)[/hide] [hide]linky to sequence A001597[/hide] (http://www.research.att.com/~njas/sequences/A001597) Actually, [hide]Should this even be in medium? Cause it's little more than "guess the theorem" I doubt anyone here can be expected to prove it.[/hide] |
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Title: Re: Subtract The Expressions, Get 1 Post by Eigenray on Jun 30th, 2008, 7:25pm Note that we can factor this in more ways if [hide](Q+1) is odd or (R+1) is even[/hide]. Actually, these both must be the case. on 06/30/08 at 13:37:14, towr wrote:
But this is only a special case of Catalan's conjecture (see [link=http://www.ocf.berkeley.edu/%7Ewwu/cgi-bin/yabb/YaBB.cgi?board=riddles_medium;action=display;num=1184647059]here[/link] for another one). There is an elementary proof. |
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