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        riddles >> medium >> n = (x+y+z)^2/(xyz)
        
(Message started by: wonderful on Jun 23rd, 2008, 2:48pm)
Title: n = (x+y+z)^2/(xyz)
Post by wonderful on Jun 23rd, 2008, 2:48pm
Find all natural number(s) n  satisfying the above equation given x, y, z are natural.

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Title: Re: n = (x+y+z)^2/(xyz)
Post by Eigenray on Jun 27th, 2008, 6:33pm
Nobody?  The solution is much like the solution to the problem this problem is much like.
Title: Re: n = (x+y+z)^2/(xyz)
Post by wonderful on Jun 29th, 2008, 8:33pm
Yes, this question  can be solved using a method very similar to Eigenray's solution.  Hint: [hide](x, y, z) is a solution then (x, y, (x+y)^2/z) is also.[/hide]

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