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Title: Proof (?) of Fermat's Last Theorem Post by cool_joh on Dec 19th, 2007, 7:39pm an+bn=cn an-0n=cn-bn n=3, sequence of power: 0, 1, 8, 27, 64, 125 n=4, seq: 0, 1, 16, 81, 256... and so on. Note that the difference goes larger as the sequence goes higher. So it's impossible that there are two pairs of terms which has the same differences. Sorry about my poor English, I hope you understand. But, I doubt that this really prove the theorem. Can anyone find any mistakes? ---inspired by nick (http://www.qbyte.org/puzzles/p061s.html) |
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Title: Re: Proof (?) of Fermat's Last Theorem Post by Obob on Dec 19th, 2007, 9:33pm The logic just plain doesn't work, is what the error is. By the exact same argument, a2+b2=c2 shouldn't have any solutions either, which is absurd. There is no obvious reason why the difference of two terms in the n=4 sequence shouldn't again be in the n=4 sequence, for instance. |
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Title: Re: Proof (?) of Fermat's Last Theorem Post by Hippo on Dec 20th, 2007, 4:17am on 12/19/07 at 19:39:36, cool_joh wrote:
Noone talks about differences of neighbouring members. ... |
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Title: Re: Proof (?) of Fermat's Last Theorem Post by SMQ on Dec 20th, 2007, 5:42am on 12/19/07 at 19:39:36, cool_joh wrote:
But that's just as true of the sequence of squares: 0, 1, 4, 9, 16, 25, ... yet 9 + 16 = 25 (and those are even adjacent terms!). --SMQ |
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Title: Re: Proof (?) of Fermat's Last Theorem Post by Grimbal on Dec 20th, 2007, 6:35am It also happens that 123-93 = 103-13 |
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Title: Re: Proof (?) of Fermat's Last Theorem Post by FiBsTeR on Dec 20th, 2007, 5:11pm on 12/20/07 at 06:35:33, Grimbal wrote:
Dr. Taxicab (http://www.ocf.berkeley.edu/~wwu/cgi-bin/yabb/YaBB.cgi?board=riddles_easy;action=display;num=1194039906) would be proud. :'( |
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