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Title: product of the roots Post by tony123 on Nov 7th, 2007, 11:58am prove the product of the roots of 50x^50+ 49x^49+ · · · + x + 1 = 0. is= 1/50. |
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Title: Re: product of the roots Post by Aryabhatta on Nov 7th, 2007, 12:01pm If I understood the question correctly, this is a basic question and I believe should be in easy. |
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Title: Re: product of the roots Post by pex on Nov 7th, 2007, 12:24pm on 11/07/07 at 12:01:48, Aryabhatta wrote:
I agree. Just to be thorough: [hideb]Let the roots be r1, r2, ..., r50. By the Fundamental Theorem of Algebra, 50x50 + 49x49 + ... + x + 1 = 50(x-r1)(x-r2)...(x-r50). Multiplying out, we see that the constant term is 50r1r2...r50. As the constant term needs to be equal to one, the result follows.[/hideb] |
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Title: Re: product of the roots Post by Grimbal on Nov 8th, 2007, 1:28am And what would be the sum of the roots? ::) |
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