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Title: solve 2 Post by tony123 on Jun 29th, 2007, 6:46am sqrt(5 - x) +x^2 = 5 |
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Title: Re: solve 2 Post by jollytall on Jun 29th, 2007, 12:01pm if you do: sqrt(5-x) = 5-x2 then squere it (requires 5-x>0 and 5-x2>0, see backtesting later) 5-x=25-10x2+x4 then x4-10x2+x+20=0 or (x2+x-5)*(x2-x-4)=0 then from here you have four potential solutions. All the four have 5-x>0, but two have not 5-x2>0. So the two solutions: (sqrt(21)-1)/2 and (1-sqrt(17))/2 |
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