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Title: Four Liars Post by THUDandBLUNDER on Nov 5th, 2003, 5:22am Four people, A, B, C, and D, each tell the truth, independently of one another, with a probability of 1/3. If A states that B denies that C says that D is lying, what is the probability that D is telling the truth? |
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Title: Re: Four Liars Post by towr on Nov 5th, 2003, 5:38am Can we assume D actually said anything? (because C could say D was lying even if D didn't say anything) this is all terribly complicated.. |
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Title: Re: Four Liars Post by THUDandBLUNDER on Nov 5th, 2003, 5:51am Quote:
Good point. Assumptions: 1) D said something which can be regarded as either true or false. 2) C can accurately assess the truth or otherwise of D's statement and make his/her own. |
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Title: Re: Four Liars Post by rmsgrey on Nov 14th, 2003, 7:17am Another assumption appears to be needed: 3) B made a statement concerning C's statement Possibly also: 4) Neither A nor B make statements without knowing whether they are true. |
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Title: Re: Four Liars Post by THUDandBLUNDER on Nov 14th, 2003, 8:20am Quote:
"B denies that C says" seems to cover that. Quote:
A's statement relates only to what B said (not to what D said), and B's statement relates only to what C said (not to what D said). In that sense, they both know 'the truth' of what they heard. |
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Title: Re: Four Liars Post by visitor on Nov 14th, 2003, 8:31am So does anybody actually plan on answering the question? The actual probability assigned to D is immaterial, because c knows for a fact whether it's true or false. The statement is equivalent to A states that b states that c states that d is telling the truth. Therefore there are 4 ways d could be telling the truth: If a,b,c were all right (probability 1/27) If any two of them were wrong (probability 4/27 times 3). Total 13/27 |
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Title: Re: Four Liars Post by THUDandBLUNDER on Nov 14th, 2003, 8:45am Quote:
That is correct, but IMO your answer is wrong. :o |
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Title: Re: Four Liars Post by visitor on Nov 14th, 2003, 9:45am You're right. D's probability does make a difference (as I should have realized from the taxi riddle). When D is telling the truth, there's a 13/27 chance it will be correctly labeled the truth. But when D lies (2/3 of the time) there's a 14/27 chance it will be incorrectly labeled the truth. So out of 81 trials, we'll have the given statement 41 times, and it will be true 13 of those 41. Am I getting close? |
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Title: Re: Four Liars Post by towr on Nov 14th, 2003, 10:04am on 11/14/03 at 08:31:33, visitor wrote:
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Title: Re: Four Liars Post by THUDandBLUNDER on Nov 15th, 2003, 9:49pm Quote:
Yes, that's what I get. Notice that it is just a little less than if D alone had spoken. |
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Title: Re: Four Liars Post by rmsgrey on Nov 17th, 2003, 6:28am on 11/14/03 at 08:20:42, THUDandBLUNDER wrote:
But we have only A's word for it - so if B says nothing, he doesn't deny anythiing, so A's statement is trivially false... Quote:
If they heard anything, then they know what they heard, but if either of them didn't hear, or heard indistinctly, or didn't understand for some other reason (foreign language?) what was said, then they would be unable to assess the truth of their own statement. |
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Title: Re: Four Liars Post by THUDandBLUNDER on Nov 17th, 2003, 9:13pm Quote:
I thought it was obvious that this was a simple exercise in probability and logic - not in semantics, nitpicking, or pedantry. ::) |
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Title: Re: Four Liars Post by rmsgrey on Nov 20th, 2003, 6:49am Yes, but the logic and probability seem conceptually simple and just require some calculation, and since I'm too lazy to actually do them, I decided to follow Towr's lead. Since my comments were challenged, I defended them at the earliest opportunity (my internet access is a little sporadic at present) |
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