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Title: Knights - knaves variation Post by Altamira_64 on Dec 7th, 2016, 9:32am On a fictional island there are 10 inhabitants, who all know each other, of which 5 are knights, who always tell the truth and the rest of them are knaves, who always lie. A visitor to the island wants to determine the 5 knaves. What is the minimum number of yes-no questions he must ask the inhabitants in order to find the 5 knaves? |
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Title: Re: Knights - knaves variation Post by dudiobugtron on Dec 7th, 2016, 12:30pm Each question must be to only one person, I assume (otherwise it's pretty easy). The maximum is (trivially) [hide]5-9 questions[/hide], since you can just [hide]ask each person a question where its truth is common knowledge. Or, ask each person a variation of the 1 knight, 1 knave question.[/hide] |
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Title: Re: Knights - knaves variation Post by rmsgrey on Dec 7th, 2016, 2:21pm There are 252 possible ways of picking 5 knaves out of 10 inhabitants, so a general solution must take at least 8 questions to enable you to distinguish between more than 128 possibilities. With more general 10-inhabitant knight-knave islands, which have 1024 possible arrangements of knights and knaves, it's trivially both necessary and sufficient to ask 10 questions to identify them all. For this special island, you can improve the upper bound to 9 questions by observing that once you know 9 of the inhabitants' natures, you get the 10th automatically. It's not obvious whether the lower-bound of 8 questions is achievable or not. |
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Title: Re: Knights - knaves variation Post by towr on Dec 7th, 2016, 10:37pm [hide]Once you know what the first person is, you can use the next 7 questions to determine which of 126 permutations you have for the rest. And that's without resorting to tricky self-correcting questions like "Would an inhabitant that's the opposite to your type say that .... ?" You can just ask the first person whether he's a pizza, and interpret his following answers accordingly.[/hide] |
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Title: Re: Knights - knaves variation Post by Altamira_64 on Dec 7th, 2016, 11:21pm Each question must be to only one person, I assume (otherwise it's pretty easy). Correct. |
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Title: Re: Knights - knaves variation Post by rmsgrey on Dec 8th, 2016, 10:08am Yeah, on further reflection, it's obvious that you can meet the lower bound (as towr says) - the tricky part is doing so in an elegant fashion. |
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Title: Re: Knights - knaves variation Post by Altamira_64 on Dec 8th, 2016, 12:01pm So the minimum number is 8, right? |
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Title: Re: Knights - knaves variation Post by dudiobugtron on Dec 8th, 2016, 12:02pm I think this question should always generate a correct answer as to whether the arrangement of knights and knaves fits a particular criterion, regardless of whether the person you ask is a knight or a knave: [hide]Is the following true: ("You are a knight" and "The arrangement of knights and knaves fits criterion X") or ("You are a knave" and "The arrangement of knights and knaves does not fit criterion X") ?[/hide] I'm sure there is a more elegant way to ask it though! |
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Title: Re: Knights - knaves variation Post by towr on Dec 8th, 2016, 1:05pm on 12/08/16 at 12:01:43, Altamira_64 wrote:
On the other hand, if you can give instructions via a yes-no question and they're willing to follow them, then you might be able to do better: "Will you please separate the inhabitants of this island into two groups, one consisting of only knaves and the other consisting of only knights?" If the answer is yes, and the corresponding instruction is followed, well, you still won't know if it's true, but you're getting somewhere. |
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Title: Re: Knights - knaves variation Post by rmsgrey on Dec 9th, 2016, 8:34am So, best approach we've come up with so far is: 1) Ask someone a question that identifies them 2) Ask that person "are the inhabitants of this island one of these 64 possibilities?" and then list 64 different possibilities. 3) Ask that person about a list of 32 possibilities 4) 16 5) 8 6) 4 7) 2 8) 1 The real question is how far those lists of possibilities can be compressed into something more elegant... |
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Title: Re: Knights - knaves variation Post by rloginunix on Dec 9th, 2016, 10:20am Can any advantage be squeezed out of forcing a predetermined geometric formation onto the remaining 9 suspects - by placing them, say, along a circumference of a circle and crafting the lists accordingly? |
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Title: Re: Knights - knaves variation Post by dudiobugtron on Dec 9th, 2016, 2:33pm on 12/09/16 at 10:20:59, rloginunix wrote:
For elegance - yes. EG: "Are there more knights to your right than to your left?", etc... But you can't reduce the required number of steps this way. |
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