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Title: Dissecting a heronian triangle Post by JocK on Aug 18th, 2005, 12:20pm Can you dissect a Heronian triangle into three Heronian triangles? |
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Title: Re: Dissecting a heronian triangle Post by Barukh on Aug 18th, 2005, 11:12pm Yes. Moreover, I think Heronian triangle can be dissected into any number of Heronian triangles. JocK, do you want to strenghthen the requirements? |
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Title: Re: Dissecting a heronian triangle Post by Grimbal on Aug 19th, 2005, 1:41am If you know a way to dissect a heronian triangle into 2 heronian triangles, it is trivial to dissect one into n heronian triangles. Whatever a heronian triangle is... ::) |
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Title: Re: Dissecting a heronian triangle Post by Grimbal on Aug 19th, 2005, 4:12am Funny. I reread the question and I see it asks to cut the triangle in 3. I would have sworn it said to cut it in 2, which explains my remark. |
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Title: Re: Dissecting a heronian triangle Post by Grimbal on Aug 19th, 2005, 4:20am This should work: If you have a triange ABC, where AB<AC, construct a similar A'B'C', mirror reversed and scaled down, such that A' = A, C' = B, B' is on AC. This cuts the triangle in 2. Repeat to have 3 pieces. All sides should be rational, as are the surfaces. It doesn't work for the equilateral triangle, but it isn't heronian anyway. |
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Title: Re: Dissecting a heronian triangle Post by JocK on Aug 19th, 2005, 1:24pm on 08/18/05 at 23:12:04, Barukh wrote:
Sure... ;D ... the follow-up question is: Can you dissect a Heronian triangle in three Heronian triangles such that the resulting triangles have equal area? (The much harder follow-up question I leave for later... ;) ) |
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Title: Re: Dissecting a heronian triangle Post by Barukh on Aug 22nd, 2005, 9:54am I don't know what is the much harder follow-up, but this equal-area variation is hard enough (at least for me). The more I look at this problem, the more I think that the answer is "no", but cannot prove it. What I succeeded to show is that certain dissections (e.g. depicted below) are impossible. Any comments? |
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