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Title: Seeing double Post by BenVitale on Dec 31st, 2009, 4:38am Say we have a 3-digit number A = xyz Is it possible to get a square by writing twice the same natural number? I mean from A = xyz to B = xyzxyz (now a 6-digit number) My question is : could we get a number B being a square? For example, if A = 123, then B = 123123 is not a square Similarly if A = 456, B = 456456 : it is not a square. |
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Title: Re: Seeing double Post by ThudanBlunder on Dec 31st, 2009, 4:52am Consider that B = 1001A = 7*11*13*A |
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Title: Re: Seeing double Post by MathsForFun on Jan 1st, 2010, 3:07am on 12/31/09 at 04:38:38, BenVitale wrote:
No. |
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Title: Re: Seeing double Post by Immanuel_Bonfils on Jan 20th, 2010, 4:06pm on 12/31/09 at 04:52:10, ThudanBlunder wrote:
Almost: 1002001 |
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