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Title: Interesting interest Post by Noke Lieu on Mar 10th, 2009, 9:18pm A new bank has opened in Cuckooland, where interest is calculated and added daily. It lets you name your compound interest rate (under 20%) for deposits. The only catch is that it'll offer you double that rate to take it as simple interest instead. As expected, Simple interest starts off winning. After how many days does it pay better to have chosen Compound interest? |
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Title: Re: Interesting Post by towr on Mar 11th, 2009, 2:23am The interest rate is per day? Then [hide]after ~7.7 days compound is better than simple. Unless you withdraw your deposit each day and then (have a friend) deposit it again :P[/hide] |
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Title: Re: Interesting Post by Immanuel_Bonfils on Mar 11th, 2009, 5:43pm Seems the rate is less than 20% and not 20%... (I don't know why) |
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Title: Re: Interesting Post by Noke Lieu on Mar 11th, 2009, 6:14pm Towr... I have a different answer. Either I've completely lost the plot (given the events of this morning, entirely plausible), or what I was expecting to ask wasn't quite what you've answered. Even if I plug in to Excel (oh dear) 100 . 100 =a1*1.1 . 120 =a2*1.1 . 140 at day 15 it's 379.75 vs 380.... |
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Title: Re: Interesting Post by towr on Mar 12th, 2009, 2:04am on 03/11/09 at 18:14:41, Noke Lieu wrote:
I did 1.20n vs 1+0.40*n, since in the limit 20 is the highest interest rate you can get, and a higher interest rate is always better to get than a lower one. n=7 : 3.5832 vs 3.8 n=8 : 4.2998 vs 4.2 |
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Title: Re: Interesting Post by Noke Lieu on Mar 12th, 2009, 3:59pm well, yeah. That's what that does, except it's (1.1)n vs (1.2)n Yes, for taking 20%, 7.7 days is what I get too. But that's only for 20%. at 10%, it's much longer. Why not takethe 20%? who knows. It's cuckooland, after all. perhaps somewhere in the fine print, it says we take as many fingers as you claim in percent interest... |
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Title: Re: Interesting Post by towr on Mar 12th, 2009, 4:14pm on 03/12/09 at 15:59:51, Noke Lieu wrote:
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Title: Re: Interesting Post by Noke Lieu on Mar 12th, 2009, 5:26pm hence, what I was after was the solution to (1+I/100)n = (1 + 2I/100)n, giving n in terms of I, or somesuch. as I approches 0, compound interest wins out as In approaches...? I was trying to dust off how to use logs, having not done them formally in years and years. and failing. |
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Title: Re: Interesting Post by towr on Mar 13th, 2009, 1:06am on 03/12/09 at 17:26:11, Noke Lieu wrote:
You can get decent approximations without it, but even that goes beyond mere logarithms. Such as perhaps using a Taylor expansion to approximate (1+I/100)n for small I. |
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