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Title: Angles in GP Post by ronnodas on Mar 2nd, 2009, 7:21pm All points on a plane are colored with three colors. Prove that there exist an infinite number of triangles on the plane with all vertices the same color, that are either isosceles or have their angles in geometric progression. Prove the statement when geometric progression is replaced by arithmetic progression and degenerate triangles are allowed. |
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Title: Re: Angles in GP Post by ronnodas on Mar 8th, 2009, 11:59pm No takers? The problems are variations of one given in this year's Indian Math Olympiad. |
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Title: Re: Angles in GP Post by towr on Mar 9th, 2009, 4:03am Here (http://www.ocf.berkeley.edu/~wwu/cgi-bin/yabb/YaBB.cgi?board=riddles_easy;action=display;num=1083267737)'s a thread that deal with two-colored plane. In that case it applies to any triangle. |
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Title: Re: Angles in GP Post by towr on Mar 9th, 2009, 8:45am We can use the idea used at this site (http://skepticsplay.blogspot.com/2008/09/monochromatic-triangles-in-multi.html). It may be interesting to do it without using [hide]Van der Waerden's Theorem[/hide] (http://mathworld.wolfram.com/vanderWaerdensTheorem.html), using the given properties, but I haven't any ideas. |
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Title: Re: Angles in GP Post by ronnodas on Mar 9th, 2009, 9:58am Yeah, the problems are similar. Both of these can be solved with [hide]7 points in very symmetric configurations[/hide]. |
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