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Title: Difficult item Post by Karotto on Jun 29th, 2008, 3:34am Can you solve this? (Click the image for zoom) http://img524.imageshack.us/img524/599/matrixc14ey4.th.gif (http://img524.imageshack.us/my.php?image=matrixc14ey4.gif) Thanks |
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Title: Re: Difficult item Post by Wardub on Jun 29th, 2008, 5:58am My guess is A. Labeling the squares as follows 123 456 789 [hide]Reasoning: It looks like the pairs across each other are the same, and the blue circles total 3. If you look at(2,8) (4,6) (3,7) there the same image and blue dots = 3. Now 1 has 2 dots on top then 1 on the bottom with 0 blue dots. So number 9 should be the same image as 1 with 3 dots. A has 3 dots and 3 blue dots, but its upside down. So really the pairs aren't the same but they are flipped over a horizontal axis. [/hide] Or maybe I am out of my mind, and that only made sense to me. ??? |
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Title: Re: Difficult item Post by Immanuel_Bonfils on Jun 29th, 2008, 11:53am A, for a central symmetry. I didn't notice the blue dots. Let us think about... Seems that the number of blue dotas must be three for each symmetric pair. I just don undestand why this problem is hard? |
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Title: Re: Difficult item Post by Hippo on Jun 29th, 2008, 12:35pm But why on 7 there are 2 blue dots? And why the positioning of blue dots changes ... and yes, it does not belong to hard. |
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Title: Re: Difficult item Post by towr on Jun 29th, 2008, 2:29pm on 06/29/08 at 11:53:03, Immanuel_Bonfils wrote:
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