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Title: Fold Octagon Post by Noke Lieu on Feb 24th, 2005, 3:29pm Starting with a square piece of paper, what is the minimum number of folds that you'd need to ensure that you've folded a regular hexagon (assume 0 thickness of paper)? Lets count the final number of creases in the paper as the number of folds. |
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Title: Re: Fold Octagon Post by Grimbal on Feb 25th, 2005, 1:14am An octogon or a hexagon? If you fold a paper in 4, does it count as 2 folds or 3? Can you assume you can fold wherever you want, or do you want a method to fold a perfect hexagon without any measuring tool? If yes and yes, I find [hide]8[/hide] folds. |
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Title: Re: Fold Octagon Post by Noke Lieu on Feb 27th, 2005, 2:42pm Ooops, octagon first (hexagon was for first follow up) IF you fold paper in 4, depends how you fol dit, I guess. :P Such that you fold it, resulting in 4 identical squares, thats 2 folds. No measuring tools, just lining up and folding. |
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Title: Re: Fold Octagon Post by Grimbal on Feb 28th, 2005, 12:36am 4 folds are obviously enough for an octogon, but I would need 3 more to locate the right place to fold. |
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