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riddles >> easy >> Differentiation Problem
(Message started by: THUDandBLUNDER on Dec 3rd, 2003, 11:23pm)

Title: Differentiation Problem
Post by THUDandBLUNDER on Dec 3rd, 2003, 11:23pm
Let
z = xx
and y = xz

Find dy/dx

Title: Re: Differentiation Problem
Post by TenaliRaman on Dec 4th, 2003, 1:43am
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isn't the simple chain differentiation stuff? or is there anything intricate i am missing.
y=xz
lny=zlnx
(1/y)(dy/dx)=z/x + lnx(dz/dx) ..(*)

z = xx
lnz = xlnx
(1/z)(dz/dx) = 1+ln(x) .. (**)

subbing (**) in (*) and rearranging,
(dy/dx) = xx^x+x*(lnx)2 + xx^x+x*(lnx) + xx^x+x-1
[/hide]::

Title: Re: Differentiation Problem
Post by towr on Dec 4th, 2003, 2:22am
yep.. that seem about right..

this also work
::[hide]
(d/dx x^a^a + a^x^a + a^a^x)[a:=x]
[/hide]::
It probably gives some people the wrong idea though..



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