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Title: Differentiation Problem Post by THUDandBLUNDER on Dec 3rd, 2003, 11:23pm Let z = xx and y = xz Find dy/dx |
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Title: Re: Differentiation Problem Post by TenaliRaman on Dec 4th, 2003, 1:43am ::[hide] isn't the simple chain differentiation stuff? or is there anything intricate i am missing. y=xz lny=zlnx (1/y)(dy/dx)=z/x + lnx(dz/dx) ..(*) z = xx lnz = xlnx (1/z)(dz/dx) = 1+ln(x) .. (**) subbing (**) in (*) and rearranging, (dy/dx) = xx^x+x*(lnx)2 + xx^x+x*(lnx) + xx^x+x-1 [/hide]:: |
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Title: Re: Differentiation Problem Post by towr on Dec 4th, 2003, 2:22am yep.. that seem about right.. this also work ::[hide] (d/dx x^a^a + a^x^a + a^a^x)[a:=x] [/hide]:: It probably gives some people the wrong idea though.. |
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