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Title: Two Easy Riddles & Two Word Problems Post by Joe on Sep 21st, 2003, 3:55pm 1.People have it - girls and ladies always, men and boys never, althought Larry certianly had it first, and Bill had is twice. What is it? 2.On the galleon there were a number of ship's cats, a number of pirates, the cook, and the one-legged captain. Altogether therer were 15 heads and 41 legs. How many ships cats were there. 3.By the time the sailing ship had made five voyages, it had carried a total of 500 passengers. There were 190 passengers altogether on the forst two voyages, 155 passengers altogether on the seconds and third voyages, 210 passengers altogether on the third and fourth voyages, and 225 passengers altogeth on the fourth and fifty voyages. How many passengers were on the ship on its third voyage? 4.One of the men coming out of the catina was overheard to say to other, "There are two bandits in there, and one of them is the father of the other's son!" Can you explain how this could happen? //Title changed and Thread moved from the Hard Forum by Icarus - Please use descriptive titles. |
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Title: Re: Two Easy Riddles & Two Word Problems Post by Icarus on Sep 21st, 2003, 9:07pm I'll give you some hints Joe. Use your mouse to select the hidden text in order to read it. (CTRL-A will select everything). 1) Hint: [hide]This puzzle is about spelling.[/hide] 2) Hint: [hide]The cook and the captain provide 2 heads and 3 legs, leaving 13 and 38 left. Let C = # of cats, P = # of pirates. Counting total heads of cats & pirates and counting total legs of cats & pirates gives you a set of two equations in two unknowns. Solve it to find the number of cats.[/hide] 3) Hint: [hide]Let p, q, r, s, t be the number of passengers on the each of the 5 trips, in order. The first thing you are told is that p+q+r+s+t = 500. Next is p+q = 190, q+r=155, r+s=210, and s+t=225. This gives 5 equations in 5 unknowns, so you can solve it to find r.[/hide] 4) Hint: [hide]This riddle relies on cultural biases people have. This is only puzzling if you assume something about the thieves. Remove that assumption, and the only thing that doesn't make sense is why anyone would make such an odd remark about the situation.[/hide] Note: Since I know nothing about you, Joe, I may have assumed more mathematical knowledge in my hints on 2 and 3 than you currently possess. If this is the case, let me know. |
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Title: Re: Two Easy Riddles & Two Word Problems Post by Speaker on Sep 22nd, 2003, 1:10am 1: Lads and lasses have it, but kids do not. 2: There is one more pirate than cats. 3: Who knows 4: May 11, 2003. |
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Title: Re: Two Easy Riddles & Two Word Problems Post by Sir Col on Sep 22nd, 2003, 5:31am on 09/21/03 at 21:07:55, Icarus wrote:
I hadn't throught about CTRL-A; nice tip, Icarus. Alternatively, you can triple click the post! ;) Quote:
::[hide] Actually, it's a bit easier than it first appears... As p+q=190 and s+t=225, p+q+s+t=415. So, (p+q+r+s+t)–(p+q+s+t)=r=500–415=85. [/hide]:: |
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Title: Re: Two Easy Riddles & Two Word Problems Post by Icarus on Sep 22nd, 2003, 7:45pm on 09/22/03 at 01:10:47, Speaker wrote:
Okay, Speaker, you've got me. What is that about? |
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Title: Re: Two Easy Riddles & Two Word Problems Post by aero_guy on Sep 23rd, 2003, 1:50pm I am assuming it is a cetain holiday... |
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Title: Re: Two Easy Riddles & Two Word Problems Post by Speaker on Sep 23rd, 2003, 4:16pm Yes, a certain holiday. I first thought this was one of those "at least one of the others..." kind of puzzles. But, after posting and looking at it in print, the real answer came to light. |
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Title: Re: Two Easy Riddles & Two Word Problems Post by Icarus on Sep 23rd, 2003, 5:52pm Okay - I get it now. Since Joe hasn't said anything, I'm wondering if I lost him by the twin renaming and moving of his thread. (It was originally named something like "PLEASE, I NEED HELP, QUICK!!"). Perhaps I should have done the two fixes one at a time. |
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Title: Re: Two Easy Riddles & Two Word Problems Post by Speaker on Sep 23rd, 2003, 6:04pm I think your fix was fine. There is still a link in the Hard section with the original title, so he should be able to find the new thread. |
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Title: Re: Two Easy Riddles & Two Word Problems Post by Icarus on Sep 23rd, 2003, 7:09pm Actually, no - the "moved" post in the hard forum is under the new name. I made the mistake of first renaming it, then moving. If I had done it the other way around, it would be under the original name there, and I could have changed the message (which is produced automatically) to indicate the name change as well. Now though, I don't remember exactly what the original name was, so there isn't much point in changing the name of the "moved" message back. If Joe doesn't post again in the next couple weeks, I'll delete the "moved" thread anyway. Those things are pointless after awhile. (He may also be put out at my calling riddles that obviously left him stumped "easy", but it's clear that these riddles are more in the line of others in the Easy forum than anything in the Hard. If the first were by iself, I would have moved it to the "What Am I" forum.) |
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Title: Re: Two Easy Riddles & Two Word Problems Post by Sameer on Oct 1st, 2003, 8:23am I am still lost on 4... ??? |
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Title: Re: Two Easy Riddles & Two Word Problems Post by BNC on Oct 1st, 2003, 12:49pm on 10/01/03 at 08:23:24, Sameer wrote:
Sameer, Here's a BIG hint:[hide]Saying that A is B's son, may mean more than one thing about B[/hide]. |
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Title: Re: Two Easy Riddles & Two Word Problems Post by Smart Guy on Oct 3rd, 2003, 3:11am 4: The two bandits are a man and a women, parents of the son. |
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Title: Re: Two Easy Riddles & Two Word Problems Post by jtrook on Oct 3rd, 2003, 8:46am I enjoyed the first three questions. The second and third I with my 9th grade algebra class. They will make excellent warm up problems. |
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Title: Re: Two Easy Riddles & Two Word Problems Post by Nikolina Demark on Nov 21st, 2003, 10:24am I know the answer to No1. It's the letter L! Twice in BiLL, once in Larry, girLs and Ladies have it, men and boys don't. Hurray! :D |
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Title: Re: Two Easy Riddles & Two Word Problems Post by rmsgrey on Nov 22nd, 2003, 9:28pm Alternate for 4: Adoption. And then you get the SF explanations... |
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