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Title: Matches time again Post by BNC on Jul 9th, 2003, 9:53am Move 3 matches to get a valid equation: |||| - || = |||| |
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Title: Re: Matches time again Post by Steihl on Jul 9th, 2003, 11:35am ||||| - | = |||| Oh wait I only moved 1 match. |
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Title: Re: Matches time again Post by Guestibe on Jul 9th, 2003, 12:12pm Do the same as Steihl, but then swap the two rightmost matches. Total of three matches moved. Err... well, it works in a literal sense anyway. |
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Title: Re: Matches time again Post by WombatDeath on Jul 9th, 2003, 12:36pm How's this: [hide]|||| - | + | = ||[/hide] |
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Title: Re: Matches time again Post by SWF on Jul 9th, 2003, 5:07pm Moving only 2, but you can always add a trivial move, like moving the first stick in a row of four to the end. |||| X | = |||| |
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Title: Re: Matches time again Post by mistysakura on Jul 9th, 2003, 8:34pm on 07/09/03 at 12:36:56, WombatDeath wrote:
[hide]4-1+1=2? How does that work? The only way I can see it worlk is with brackets...[/hide] |
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Title: Re: Matches time again Post by BNC on Jul 9th, 2003, 9:17pm on 07/09/03 at 17:07:10, SWF wrote:
Hehe, of course the 1 match solution is trivial, but I tried to think of a 2-match solution and ask for 1-2-3 solutions, but couldn't. Nice! I had another 3-match solution in mind, though. |
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Title: Re: Matches time again Post by wowbagger on Jul 10th, 2003, 2:10am on 07/09/03 at 21:17:10, BNC wrote:
Maybe this one: [hide] _ III / \I I = III [/hide] sorry if it doesn't align quite right. plain math: [hide]3 / sqrt(1) = 3[/hide] |
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Title: Re: Matches time again Post by otter on Jul 10th, 2003, 6:25am How about [hide]X||| - | = X||[/hide]? Should only be three moves if [hide]you count changing || to X as only one move.[/hide] |
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Title: Re: Matches time again Post by WombatDeath on Jul 10th, 2003, 12:32pm on 07/09/03 at 20:34:34, mistysakura wrote:
Well, yes, but after staring at the damn thing for 20 minutes I'm surely entitled to discard such a silly notion as the left-to-right rule. No? Bah! |
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Title: Re: Matches time again Post by WombatDeath on Jul 10th, 2003, 12:48pm OK, here's one that doesn't involve cheating: [hide] ||| / ||| = || - |[/hide]. |
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Title: Re: Matches time again Post by BNC on Jul 11th, 2003, 1:23am A note: on second thought, the solution I had in mind, could also be generated moving 2 matches -- it depends on [hide]the original spacing between the matches[/hide]. |
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Title: Re: Matches time again Post by WombatDeath on Jul 11th, 2003, 12:01pm on 07/11/03 at 01:23:51, BNC wrote:
Was it [hide]|+|-| = ||/||[/hide]? That can be achieved in either two or three moves, depending on whether [hide]the sixth (or seventh, if you prefer) match is used as the dividing symbol or just stuck on the end of the equation[/hide]. The first method (two moves) only works if [hide]you allow sufficient spacing[/hide]. |
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Title: Re: Matches time again Post by BNC on Jul 11th, 2003, 12:13pm 1. Many answers fit perfectly. In fact, many more than I thought! 2. A hint for the 'original' solution: [hide]some roman numerals look similar to decimal, while other don't[/hide]. |
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Title: Re: Matches time again Post by TenaliRaman on Jul 14th, 2003, 4:40am This may not be the original intended answer. [Hide] ||| - | = || |--| 111-1=110 [/Hide] |
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Title: Re: Matches time again Post by BNC on Jul 16th, 2003, 2:52am on 07/14/03 at 04:40:20, TenaliRaman wrote:
Actually, yes, it is. |
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Title: Re: Matches time again Post by TenaliRaman on Jul 17th, 2003, 10:41am yeehaw!! :) |
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