|
||
Title: japanese kindergarten Post by esha on May 20th, 2003, 10:30pm I think i figured it out. but not sure if i am right. ok . for all prime numbers it is 0; for all non prime numbers it is it is (#of prime decomposition terms -1 *2); i know it sounds complicated..but for example: 4 = 2*2; so two terms. 2-1 = 1; 1+1 =2; 8 = 2*2*2 ; so now three terms. 3-1 =2; 2+2 = 4; 9 = 3*3; so two terms. 2-1 = 1; 1+1 = 2. so then 10 + 10 would be.. 10 = 2*5 so two terms. so 10+10 = 2. is this right?? |
||
Title: Re: japanese kindergarten Post by BNC on May 21st, 2003, 12:29am There is an existing thread (http://www.ocf.berkeley.edu/~wwu/cgi-bin/yabb/YaBB.cgi?board=riddles_easy;action=display;num=1043044210;start=), including this solution. |
||
Title: Re: japanese kindergarten Post by Demos on May 27th, 2003, 11:57pm Think KINDI. When I was a kid I coloured in the enclosed areas of numbers and letters. The sums are a simple count of the number of enclosed areas to colour in. eg 1+1 = 0 (there are no areas to colour in) 2+2 = 0 (again nothing) 3+3 = 0 4+4 = 2 (look 2 triangles to colour in) 5+5 = 0 6+6 = 2 7+7 = 0 8+8 = 4 (the number 8 has 2 enclosed reagions each making 4) 9+9 = 2 10+10 = 2 (the two 0 reagions) That's what I think anyway.... |
||
Powered by YaBB 1 Gold - SP 1.4! Forum software copyright © 2000-2004 Yet another Bulletin Board |