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        riddles >> easy >> 24? I cant get 24 with 7,7,3,3
        
(Message started by: Oros24 on Apr 28th, 2003, 10:44pm)
Title: 24? I cant get 24 with 7,7,3,3
Post by Oros24 on Apr 28th, 2003, 10:44pm
??? Can someone please tell me how I am suppose to get 24, using 7, 7, 3 and 3 once each.

Thanx!
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by towr on Apr 28th, 2003, 11:24pm
how about [hide](3+3/7)*7 = 21+3[/hide] = 24
I think it's allready at the site somewhere, cause I don't usually know the answer :P
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by josh k. on May 2nd, 2003, 12:49pm

on 04/28/03 at 22:44:54, Oros24 wrote:
??? Can someone please tell me how I am suppose to get 24, using 7, 7, 3 and 3 once each.

Thanx!

You could 7 x 3= 21 + 3 = 24
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by LZJ on May 2nd, 2003, 6:05pm
You must use all 4 numbers once, and once only.
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by Al Moreno on May 13th, 2003, 12:11pm
How about:
(7*3)+3!-3=24.
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by Al_Moreno on May 13th, 2003, 12:19pm
Oops! I guess I'm not using all the numbers only once...  :'(
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by Al_Moreno on May 13th, 2003, 2:10pm
Okay.  How's This?

(sqrt(7 * 7 ) – sqrt( 3 * 3 ))! = 4! = 24
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by towr on May 13th, 2003, 11:54pm
Usually you're only allowed to use +, -, * and  /
So no sqrt, ^ or ! and such
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by HiFermat on Mar 25th, 2004, 2:01am
::) (3 + 3/7 )*7 = ( 24/7 )*7 =24
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by Benoit_Mandelbrot on Mar 25th, 2004, 9:10am
Since that one is solved, see if there is a way to get 2, 3, and 4 into 42 using any method.  You can use only 2, 3, and 4.
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by Sameer on Mar 25th, 2004, 10:06am
Hmm is it
:: [hide]
ceil(log10((32*4)!))
[/hide] ::
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by Sir Col on Mar 25th, 2004, 11:45am
A slightly easier solution would be, [hide]2*4!–3![/hide], but I thought these problems are supposed to be solved with the basic arithmetic operations?
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by Benoit_Mandelbrot on Mar 25th, 2004, 12:44pm
Here is another one for you::[hide][int]24(x[sup3]-x-x-x)dx=42. [/hide]::
Title: Re: 24? I cant get 24 with 7,7,3,3
Post by Perfection on Mar 29th, 2004, 8:21pm
I like this one the best
:P
[hide] (3+2-4)(logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+
logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+
logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx+logxx) [/hide]


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