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Title: count numbers that have prime # of bits set Post by inexorable on Oct 24th, 2007, 4:32pm consider a function P(x) where: P(x) returns: true if the number of 1 bits set in the binary representation of x is prime, false otherwise. For example, P(239) returns true, while P(51) returns false. Next, consider the following function prime_bits: uint64_t prime_bits(uint64_t a, uint64_t b); A call to prime_bits(a, b) returns the number of values between a and b inclusive for which P(x) is true. For example, prime_bits(4, 10) returns 5, while prime_bits(137, 31415926535897) returns 7753256197126. How do you implement prime_bits(a,b) such that its running time is faster than O(n) where n=b-a ? |
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Title: Re: count numbers that have prime # of bits Post by towr on Oct 25th, 2007, 2:29am I'd look up the previous thread on the subject before implementing it.. In any case, you'd use combinatorics. |
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