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Topic: 6 for $3, 24 for $6, and 120 for $9. (Read 716 times) |
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wjl317
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6 for $3, 24 for $6, and 120 for $9.
« on: Dec 10th, 2003, 4:57pm » |
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i'm apologizing now because unlike you riddle gurus out there, this one isn't blatantly obvious to me....
You can get 6 for $3, 24 for $6, and 120 for $9. What is it?
// thread title changed by wwu
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| « Last Edit: Dec 12th, 2003, 5:04pm by william wu » |
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tseuG
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Re: help needed please
« Reply #1 on: Dec 10th, 2003, 6:32pm » |
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its the number of digits in those numbers
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josh
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its something you can buy at a hardware store
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nick w
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i dont get it
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tseuG
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Re: 6 for $3, 24 for $6, and 120 for $9.
« Reply #4 on: Dec 14th, 2003, 1:08am » |
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think addresses
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John_Gaughan
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Behold, the power of cheese!
    
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Re: 6 for $3, 24 for $6, and 120 for $9.
« Reply #5 on: Dec 14th, 2003, 7:14pm » |
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Aha, that's easy now. :: Those little black letters you put on your house to show your address number. Each digit costs three dollars. ::
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x = (0x2B | ~0x2B)
x == the_question
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R.
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Re: 6 for $3, 24 for $6, and 120 for $9.
« Reply #6 on: Feb 2nd, 2004, 2:01pm » |
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I CALL SHENANAGINS!
The numbers 6 24 and 120 are 3! 4! and 5! (1*2*3 , 1*2*3*4, 1*2*3*4*5). This caused 5, yes countem 5 migranes spread out among 3 MSs and 2 PHDs.
This riddle is UNFAIR to overly analytical people!.
R,
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John_Gaughan
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Re: 6 for $3, 24 for $6, and 120 for $9.
« Reply #7 on: Feb 2nd, 2004, 9:51pm » |
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on Feb 2nd, 2004, 2:01pm, R. wrote:| The numbers 6 24 and 120 are 3! 4! and 5! (1*2*3 , 1*2*3*4, 1*2*3*4*5). |
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I didn't realize the relationship between the factorials. I guess I'm not overly analytic enough 
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Icarus
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Re: 6 for $3, 24 for $6, and 120 for $9.
« Reply #8 on: Feb 3rd, 2004, 6:19pm » |
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Anyone can get sidetracked by coincidences, or by having so many tools that one tends to pull out the most powerful even though a simpler one would be a better choice.
It is exactly this fact that makes the "trainwreck" puzzle (wherein a bird/insect flies back and forth between two trains until they collide) interesting. The problem is solved by an easy calculation, but anyone with calculus experience at least thinks of setting up and summing the infinite series. If they realize the easy means, it is only because they are wise enough to look around a bit before diving into the more obvious calculation. On the other hand, those with only algebra do not fall so readily into the trap, since the easy way is the only tool they have.
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"Pi goes on and on and on ...
And e is just as cursed.
I wonder: Which is larger
When their digits are reversed? " - Anonymous
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