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Topic: SIGMAarctan(2/n^2) (Read 1653 times) |
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ThudnBlunder
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SIGMAarctan(2/n^2)
« on: May 20th, 2008, 5:37am » |
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Evaluate tan-1(2/n2) n=1
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THE MEEK SHALL INHERIT THE EARTH.....................................................................er, if that's all right with the rest of you.
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Barukh
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Re: SIGMAarctan(2/n^2)
« Reply #1 on: May 20th, 2008, 10:44am » |
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135o
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ThudnBlunder
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Re: SIGMAarctan(2/n^2)
« Reply #2 on: May 20th, 2008, 10:52am » |
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on May 20th, 2008, 10:44am, Barukh wrote: Was that computer-assisted?
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THE MEEK SHALL INHERIT THE EARTH.....................................................................er, if that's all right with the rest of you.
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Barukh
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Re: SIGMAarctan(2/n^2)
« Reply #3 on: May 20th, 2008, 11:19am » |
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on May 20th, 2008, 10:52am, ThudanBlunder wrote: Was that computer-assisted? |
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ThudnBlunder
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Re: SIGMAarctan(2/n^2)
« Reply #4 on: May 20th, 2008, 11:27am » |
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on May 20th, 2008, 11:19am, Barukh wrote: Then I'm beginning to believe our literary tastes are similar.
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THE MEEK SHALL INHERIT THE EARTH.....................................................................er, if that's all right with the rest of you.
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Barukh
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Re: SIGMAarctan(2/n^2)
« Reply #5 on: May 20th, 2008, 11:14pm » |
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hidden: | Solution is based on the following identity: tan-1(2/n2) = tan-1(n+1) - tan-1(n-1) |
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Eigenray
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Re: SIGMAarctan(2/n^2)
« Reply #6 on: May 21st, 2008, 2:45am » |
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Or less cleverly, working out the first few partial sums suggests hidden: | arctan{-(n-1)(n+2)/[n(n-3)]} + arctan{2/n2} = arctan{-n(n+3)/[(n+1)(n-2)]} |
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william wu
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Re: SIGMAarctan(2/n^2)
« Reply #7 on: May 21st, 2008, 3:59am » |
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Digression: As a knee jerk reaction, I took the derivative of the summand, and tried summing that instead. Not that that would lead to anything relevant for this problem ... but I ended up with something that surprised me: d/dx [ArcTan[2/x^2]] = -(4 x)/(4 + x^4) -(4 n)/(4 + n^4) = -3/2 OK, now someone explain why I shouldn't be surprised
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« Last Edit: May 21st, 2008, 4:00am by william wu » |
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[ wu ] : http://wuriddles.com / http://forums.wuriddles.com
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