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   Author  Topic: Magic Matrix Square  (Read 509 times)
JocK
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Magic Matrix Square  
« on: May 22nd, 2006, 1:13pm »
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Find nine nxn matrices Ai,j such that when placed in a 3x3 square:
 
A1,1  A1,2  A1,3  
A2,1  A2,2  A2,3  
A3,1  A3,2  A3,3  
 
the product of the matrices in a row equal the unit matrix:
 
Ak,1 Ak,2 Ak,3  =  1  
 
(k = 1,2,3), whilst the product of the matrices in a column yield minus the unit matrix:
 
A1,k A2,k A3,k  =  -1
 
What is the smallest matrix dimension n for which such a magic square can be formed?
 
 
« Last Edit: May 22nd, 2006, 1:16pm by JocK » IP Logged

solving abstract problems is like sex: it may occasionally have some practical use, but that is not why we do it.

xy - y = x5 - y4 - y3 = 20; x>0, y>0.
Sjoerd Job Postmus
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Re: Magic Matrix Square  
« Reply #1 on: May 22nd, 2006, 1:27pm »
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on May 22nd, 2006, 1:13pm, JocK wrote:
Find nine nxn matrices Ai,j such that when placed in a 3x3 square:
 
A1,1  A1,2  A1,3  
A2,1  A2,2  A2,3  
A3,1  A3,2  A3,3  
 
the product of the matrices in a row equal the unit matrix:
 
Ak,1 Ak,2 Ak,3  =  1  
 
(k = 1,2,3), whilst the product of the matrices in a column yield minus the unit matrix:
 
A1,k A2,k A3,k  =  -1
 
What is the smallest matrix dimension n for which such a magic square can be formed?
 
 
 

Wouldn't  
hidden:
-1 -1 -1
-1 -1 -1
1   1   1

satisfy the equation?
At least, I assume -1 * -1 = 1
 
So -1 * -1 * 1 = 1
And -1 * -1 * -1 = -1
 
Or maybe I'm being too obvious Wink
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JocK
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Re: Magic Matrix Square  
« Reply #2 on: May 22nd, 2006, 2:13pm »
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on May 22nd, 2006, 1:27pm, Sjoerd Job Postmus wrote:

Wouldn't  
-1 -1 -1
-1 -1 -1
1   1   1
satisfy the equation?

 
All columns lead to a product +1, and most rows lead to a product -1. However, not all rows do (the last row doesn't) ...
 
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solving abstract problems is like sex: it may occasionally have some practical use, but that is not why we do it.

xy - y = x5 - y4 - y3 = 20; x>0, y>0.
Grimbal
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Re: Magic Matrix Square  
« Reply #3 on: May 24th, 2006, 6:04am »
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hidden:
+------+------+------+
| 1  0 |-1  0 |-1  0 |
| 0  1 | 0  1 | 0  1 |
+------+------+------+
| 0 -1 | 1  0 | 0  1 |
| 1  0 | 0  1 |-1  0 |
+------+------+------+
| 0 -1 | 1  0 | 0  1 |
| 1  0 | 0 -1 | 1  0 |
+------+------+------+
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JocK
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Re: Magic Matrix Square  
« Reply #4 on: May 24th, 2006, 11:56am »
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Well done, ... but ....
 
... within the third row (and within the third column) not all matrices commute. Hence, the corresponding row-product (column-product) is not unambiguously defined.
 
Can you generate a realisation such that within each row and each column all matrices commute...?
 
(Sorry, should have stated this requirement more clearly.)
 
 
 
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solving abstract problems is like sex: it may occasionally have some practical use, but that is not why we do it.

xy - y = x5 - y4 - y3 = 20; x>0, y>0.
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