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Topic: Probably easy limit question (Read 2282 times) |
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Lizzy
Newbie
Posts: 5
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Probably easy limit question
« on: Mar 20th, 2006, 7:00pm » |
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Hey guys, this will probably be really easy for u...but i don't know how to do it Find the limit of cot(2x)sin(6x) as x approaches 0 any help on how to do it will be greatly appreciated Lizzy xoxo
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Barukh
Uberpuzzler
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Posts: 2276
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Re: Probably easy limit question
« Reply #1 on: Mar 20th, 2006, 11:41pm » |
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Making a substitution z = 2x, you simplify the limit to cot(z)sin(3z), so actually you need to find the limit of sin(3z)/sin(z). Use the trigonometric identity for a triple angle to obtain the answer 3. Another way is to look at the power series for cot(x) and sin(x).
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Icarus
wu::riddles Moderator Uberpuzzler
Boldly going where even angels fear to tread.
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Re: Probably easy limit question
« Reply #2 on: Mar 21st, 2006, 3:45pm » |
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Another approach: recall the identities limz->0 (sin z)/z = 1 and limz->0 (tan z)/z = 1. The second can be rewritten as limz->0 z cot z = 1. So, lim cot 2x sin 6x = lim 3(2x cot 2x)((sin 6x)/6x) = 3 (lim 2x cot 2x)(lim (sin 6x)/6x) = 3 * 1 * 1 = 3.
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"Pi goes on and on and on ... And e is just as cursed. I wonder: Which is larger When their digits are reversed? " - Anonymous
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Lizzy
Newbie
Posts: 5
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Re: Probably easy limit question
« Reply #3 on: Mar 22nd, 2006, 2:29am » |
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yay! i understand icarus' method hmm, does anyone know any good online resources to learn this stuff properly?
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Icarus
wu::riddles Moderator Uberpuzzler
Boldly going where even angels fear to tread.
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Re: Probably easy limit question
« Reply #4 on: Mar 22nd, 2006, 6:19pm » |
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Sorry, but I don't. I learned it before the internet was easily accessible.
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"Pi goes on and on and on ... And e is just as cursed. I wonder: Which is larger When their digits are reversed? " - Anonymous
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