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Topic: Partition naturals into APs (Read 1473 times) |
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Aryabhatta
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Partition naturals into APs
« on: Aug 5th, 2005, 8:52am » |
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Can we partition the set of natural numbers into a finite number (at least 2) of arithmetic progressions, such that no two progressions have the same common difference? This is probably a well known result, but pretty interesting nevertheless.
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Icarus
wu::riddles Moderator Uberpuzzler
Boldly going where even angels fear to tread.
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Re: Partition naturals into APs
« Reply #1 on: Aug 5th, 2005, 3:05pm » |
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If you demand that your arithmetic progressions all have nth term of form nd for some fixed d, then yes, it is a very well known result! If you allow the terms to have form nd + c for some fixed d, c, then the situation is harder.
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« Last Edit: Aug 5th, 2005, 3:06pm by Icarus » |
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"Pi goes on and on and on ... And e is just as cursed. I wonder: Which is larger When their digits are reversed? " - Anonymous
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Aryabhatta
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Re: Partition naturals into APs
« Reply #2 on: Aug 5th, 2005, 5:42pm » |
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It could be nd+c. For instance one partition is 2n, 4n+1, 4n+3.
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Aryabhatta
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Re: Partition naturals into APs
« Reply #3 on: Aug 12th, 2005, 7:46pm » |
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Hint: sometimes it makes things simple to make things complex :
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Eigenray
wu::riddles Moderator Uberpuzzler
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Re: Partition naturals into APs
« Reply #4 on: Aug 15th, 2005, 1:08pm » |
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Perhaps people are remaining silent because the problem is already on this site, and they do not wish to spoil it. Anyway, both the result and its proof are far too lovely to only be listed once!
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