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Topic: rate of momentum discharge (Read 1534 times) |
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Larissa Preedy
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hey guys, having some trouble with this question i have.. can someone give me some pointers on how to solve this? or the answer if u want A fireman holds a water nozzle. The diameter of the nozzle is 0.065999m and the water exit velocity is 6.2m/s. If the density of the water is 1016 kg/m^3, what is the rate of momentum discharge from the nozzle?
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towr
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Re: rate of momentum discharge
« Reply #1 on: Jun 7th, 2005, 10:14am » |
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1 s of water is 6.2 x pi x (0.065999/2)^2 m3 ~= 0.02121 m3 0.02121 m3/s * 1016 kg/m3 ~= 21.55 kg/s 21.55 kg/s * 6.2 m/s ~= 133.6 (kg m/s)/s Though frankly I'm just guessing at what 'rate of momentum discharge' means.
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Icarus
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Re: rate of momentum discharge
« Reply #2 on: Jun 7th, 2005, 6:23pm » |
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on Jun 7th, 2005, 10:14am, towr wrote:Though frankly I'm just guessing at what 'rate of momentum discharge' means. |
| Yes - the framer of this question should be slapped a few times and told to speak proper technical English, not self-created jargon.
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"Pi goes on and on and on ... And e is just as cursed. I wonder: Which is larger When their digits are reversed? " - Anonymous
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Larrisa
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Re: rate of momentum discharge
« Reply #3 on: Jun 7th, 2005, 8:45pm » |
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on Jun 7th, 2005, 10:14am, towr wrote:1 s of water is 6.2 x pi x (0.065999/2)^2 m3 ~= 0.02121 m3 0.02121 m3/s * 1016 kg/m3 ~= 21.55 kg/s 21.55 kg/s * 6.2 m/s ~= 133.6 (kg m/s)/s Though frankly I'm just guessing at what 'rate of momentum discharge' means. |
| omg, that's exactly what i did and i kept gettin it wrong i was getting something around 534 :S but i can't see what you did difference. The units are kgm/s2 correct? and thanks heapS!
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towr
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Re: rate of momentum discharge
« Reply #4 on: Jun 8th, 2005, 2:40am » |
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Yes, or in other words N, newton. I put it explicitly as moment per second, as that seems to be what was asked for. It should just be equal to the force with which the water is pushed out of the hose. Oh, and as for what you did wrong. You seem to be off a factor 4. Which is neatly explained if you used the diameter of the nozzle instead of the radius (half the diameter) in the calculation. pi r2 = 1/4 pi d2
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« Last Edit: Jun 8th, 2005, 2:44am by towr » |
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Larissa_Preedy
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Re: rate of momentum discharge
« Reply #5 on: Jun 8th, 2005, 2:55am » |
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on Jun 8th, 2005, 2:40am, towr wrote:Oh, and as for what you did wrong. You seem to be off a factor 4. Which is neatly explained if you used the diameter of the nozzle instead of the radius (half the diameter) in the calculation. pi r2 = 1/4 pi d2 |
| omg, what a silly silly mistake!!!
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towr
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Re: rate of momentum discharge
« Reply #6 on: Jun 8th, 2005, 4:04am » |
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Meh, beats mistaking feet for meters (or vice versa) and crashing a satellite into mars.
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Larissa_Preedy
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Re: rate of momentum discharge
« Reply #7 on: Jun 8th, 2005, 6:57am » |
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LOL
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