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Topic: f(x) = 1/(1+e^x) (Read 654 times) |
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william wu
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f(x) = 1/(1+e^x)
« on: Oct 24th, 2004, 12:06am » |
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Given f(x) = 1/(1+ex), find f(100)(0). [ The f(n) notation denotes repeated application of the function. So f(2)(x) = f(f(x)). ] Edit: corrected a typo
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« Last Edit: Oct 24th, 2004, 10:24am by william wu » |
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Barukh
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Re: f(x) = 1/(1+e^x)
« Reply #1 on: Oct 24th, 2004, 12:49am » |
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Isn't it just the solution of the equation x = 1/(1+e^x)?
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william wu
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Re: f(x) = 1/(1+e^x)
« Reply #2 on: Oct 24th, 2004, 10:26am » |
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Sorry, I had a typo: it should read f(100)(0). I should warn beforehand that I haven't been able to solve this myself; hopefully the problem is legit.
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« Last Edit: Oct 24th, 2004, 10:26am by william wu » |
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Grimbal
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Re: f(x) = 1/(1+e^x)
« Reply #3 on: Oct 24th, 2004, 3:26pm » |
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It still tends quite fast to the solution of x=1/(1+e^x). It is not there yet, but close enough.
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Icarus
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Re: f(x) = 1/(1+e^x)
« Reply #4 on: Oct 24th, 2004, 3:26pm » |
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According to Excel, it is 0.401058138.... Repeated application converges to this value fairly fast. As Barukh indicates, this is the solution to x = 1/(1+ex). I would imagine it is highly unlikely that f(100)(0) is exactly the value of x solving the equation. It is very close, however. Whether or not there is "nice" expression for the number is another matter.
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"Pi goes on and on and on ... And e is just as cursed. I wonder: Which is larger When their digits are reversed? " - Anonymous
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