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vishal_changrani
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ASM question  
« on: Feb 15th, 2006, 12:07pm »
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Hi,
I am back with one more question.....supposedly asked  in an MS interview...
 
Q. The following asm block performs a common math function, what is it?
CWD XOR AX,DX
SUB AX,DX
 
My guess earlier was it is exchangin AX and DX but doesnt seemt to be that.
Also is CWD carried out first or XOR? in the first line
 
any and all replies would be appreciated.
Thank u
Vishal
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vishal_changrani
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Re: ASM question  
« Reply #1 on: Feb 15th, 2006, 12:35pm »
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Sorry but i think i found the  answer...its just doing a MOD operation Smiley
 Embarassed sorry for posting it in the first place
-vishal
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Grimbal
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Re: ASM question  
« Reply #2 on: Feb 16th, 2006, 4:22am »
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No, it does an ABS(AX)
 
In fact, it splits AX into sign and absolute value:
 
DX = sign(AX)
AX = abs(AX)
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ruhela_nitk
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Re: ASM question  
« Reply #3 on: Jul 28th, 2006, 7:48am »
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Hi  
If anyone  can explain the answer , please let me?
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Grimbal
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Re: ASM question  
« Reply #4 on: Jul 29th, 2006, 11:48am »
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CWD converts a word to double.  It does so by extending the sign of AX into DX.  Practically, it means it does DX=0 if AX is >=0 or DX=-1 (all bits set) if AX<0.
 
The XOR and SUB do nothing if DX=0.
If DX=-1, the XOR reverses all bits of AX and the SUB adds 1 to AX.  Together, it does  
  AX = (not AX) + 1
which is exactly how you compute AX=-1 in the 2's complement binary representation of integers.
 
So, the effect is to set DX=0 or -1 depending on AX's sign, and to set AX = abs(AX).
« Last Edit: Jul 29th, 2006, 11:50am by Grimbal » IP Logged
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