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   Author  Topic: LCM  (Read 655 times)
Christine
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LCM  
« on: Jun 7th, 2015, 2:51pm »
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What is the LCM of  sqrt(2) and sqrt(3) ?
 
I was told to use continued fractions, but I don't know how to do it. Help!
« Last Edit: Jun 7th, 2015, 2:52pm by Christine » IP Logged
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Re: LCM  
« Reply #1 on: Jun 7th, 2015, 5:21pm »
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on Jun 7th, 2015, 2:51pm, Christine wrote:
What is the LCM of  sqrt(2) and sqrt(3) ?

Is this even well-defined? Assuming LCM is least common multiple, which is commonly defined for integers only. I can see how to extend the concept to rationals, but for irrational numbers...
 
I suppose a common multiple would be a positive number m such that m = a*sqrt(2) = b*sqrt(3). What are a and b allowed to be? Clearly they can't both be integers, since sqrt(2/3) is irrational. But if they're not integers, nothing prevents us from replacing them by m/2 = (a/2)sqrt(2) = (b/2)sqrt(3) and no least common multiple exists.
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Re: LCM  
« Reply #2 on: Jun 7th, 2015, 10:28pm »
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Perhaps we need to find some approximate LCM, within a certain tolerance. Like: m = a*2 = b*3 with |a*2 - [a*2| < 0.01 and |b*3 - [b*3]| < 0.01, and a,b,m integers
 
So, for example  
9513*3 = 16476.9993
11651*2 = 16477.0022
So, 16477 might be considered the LCM for 2 and 3 with a given tolerance.
 
 
[edit]
Or perhaps it's simpler to consider: |m - a*2| < t and |m - b*3| < t, and a, b, m integers and some tolerance t
e.g m=134421, a=95050, b=77608, t~=0.0021
[/edit]
« Last Edit: Jun 7th, 2015, 11:07pm by towr » IP Logged

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Re: LCM  
« Reply #3 on: Jun 7th, 2015, 11:00pm »
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... and good rational approximations of irrational numbers are commonly found using continued fractions, so using towr's interpretation, the hint actually makes sense. Good mind reading! Smiley
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Re: LCM  
« Reply #4 on: Jun 7th, 2015, 11:17pm »
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Quote:
Good mind reading!
It helped that I googled a bit, I found this, for example.
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