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Topic: quadruple (Read 2299 times) |
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Christine
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Posts: 159
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Diophantus quadruple (1/16, 33/16, 17/4, 105/16) the product of any two distinct terms + 1 is a square How can you find other sets of rational quadruple?
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SEMfuze
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Re: quadruple
« Reply #1 on: Sep 27th, 2013, 7:20am » |
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y 2 = (a1x + n)(a2x + n)(a3x + n)(a4x + n)(a5x + n)
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Christine
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Posts: 159
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Re: quadruple
« Reply #2 on: Sep 27th, 2013, 9:40am » |
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on Sep 27th, 2013, 7:20am, SEMfuze wrote:y 2 = (a1x + n)(a2x + n)(a3x + n)(a4x + n)(a5x + n) |
| It doesn't look right. Maybe I miss something here. Please clarify.
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towr
wu::riddles Moderator Uberpuzzler
    
 Some people are average, some are just mean.
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Re: quadruple
« Reply #3 on: Sep 27th, 2013, 2:35pm » |
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I think he meant to copy/paste the formula for a hyperelliptic curve y2 = (a1x + 1)(a2x + 1)(a3x + n)(a4x + 1)(a5x + 1) (n=1 in this case). Equation 2 on page 2 of http://arxiv.org/pdf/math/0002088.pdf, for example (I haven't read it, and not sure how much I'd understand of it if I would).
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Wikipedia, Google, Mathworld, Integer sequence DB
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Christine
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Posts: 159
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Re: quadruple
« Reply #4 on: Sep 27th, 2013, 5:15pm » |
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on Sep 27th, 2013, 2:35pm, towr wrote:I think he meant to copy/paste the formula for a hyperelliptic curve y2 = (a1x + 1)(a2x + 1)(a3x + n)(a4x + 1)(a5x + 1) (n=1 in this case). Equation 2 on page 2 of http://arxiv.org/pdf/math/0002088.pdf, for example (I haven't read it, and not sure how much I'd understand of it if I would). |
| Ouch! Thanks. The stuff on arxiv is tough to understand. The question I posted is more difficult than I anticipated.
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