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   Squares: sums and differences
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   Author  Topic: Squares: sums and differences  (Read 1138 times)
Christine
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Squares: sums and differences  
« on: Mar 11th, 2013, 1:23pm »
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My question is: how do you find sums and differences that are both squares?
 
x + y is a square
x - y is a square
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towr
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Re: Squares: sums and differences  
« Reply #1 on: Mar 11th, 2013, 1:44pm »
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(u+v)^2-u^2 = 2uv+v^2 = 2y  
x = u^2+y
So basically we can take any u paired with an even v.
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pex
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Re: Squares: sums and differences  
« Reply #2 on: Mar 11th, 2013, 1:46pm »
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Or, equivalent but perhaps simpler: take any two squares that are either both even or both odd, say a2 and b2, and let x = (a2 + b2)/2 and y = (a2 - b2)/2.
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Immanuel_Bonfils
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Re: Squares: sums and differences  
« Reply #3 on: Mar 11th, 2013, 5:01pm »
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No restriction to x and y (unless being real, y guess), so
 
parity doesn't matter, even b>a   -> (y <0) would be OK
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Grimbal
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Re: Squares: sums and differences  
« Reply #4 on: Mar 12th, 2013, 4:00pm »
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It wasn't stated, but usually these problems ask for integer solutions.  If you are working with reals, every number >=0 is a square.
 
A simple set of solutions is x=a2 for some a and y=0.  It doesn't feel like a proper solution though.
 
On the other side, pex's method gives all integer solutions.
« Last Edit: Mar 12th, 2013, 4:02pm by Grimbal » IP Logged
Christine
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Re: Squares: sums and differences  
« Reply #5 on: Mar 19th, 2013, 10:34am »
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Thank you all for the feedback.
 
Sorry I did not state that  
> I was looking for integer solutions,
> for producing interesting results (e.g. squares of prime numbers)
 
I'll make sure that next time I'll state clearly my questions.
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