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   Is p->q->q a tautology?
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   Author  Topic: Is p->q->q a tautology?  (Read 2859 times)
techno
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Is p->q->q a tautology?  
« on: Sep 26th, 2012, 4:36pm »
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note that there are no parenthesis. Thanks for the help  Grin
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Noke Lieu
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Re: Is p->q->q a tautology?   p_to_q.png
« Reply #1 on: Sep 26th, 2012, 7:07pm »
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Depends on what you mean...
 
Not in this case.
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techno
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Re: Is p->q->q a tautology?  
« Reply #2 on: Sep 26th, 2012, 9:03pm »
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I think that's exactly what I meant. Thanks. But how would you solve it? What I did was this.
 
p->q->q
 
-p || (q->q)
 
-p || (-q||q)
 
-p || (T)
 
T.
 
Can you please explain me where I did something wrong? thanks for the help.
 
Or is it like this? I think this makes more sense but still.
 
 
p->q->q
 
(-p || q)->q
 
-(-p || q) || q
 
(p && q) || q
 
(p || q) && (q || q)
 
q && (p || q)
 
Thanks for replying so quickly.
 
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techno
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Re: Is p->q->q a tautology?  
« Reply #3 on: Sep 26th, 2012, 9:06pm »
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Actually I was wrong on the last thing I did.
 
It's  
 
(p && -q) || q
 
(q || p) && (-q || q)
 
( q || p ) && T
 
( q || p )
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peoplepower
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Re: Is p->q->q a tautology?  
« Reply #4 on: Sep 27th, 2012, 5:18am »
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A self-implication is a tautology, so implying a self-implication is still a tautology.
I have personally seen implication as a right-associative operation exclusively, where we have in general
p->(q->r) <=> ~pV(~qVr) <=> ~(p&q)Vr <=> (p&q)->r.
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techno
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Re: Is p->q->q a tautology?  
« Reply #5 on: Sep 27th, 2012, 8:56am »
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That was my main concern. So it is a right associative operation. Thanks for the help appreciate it  Smiley
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