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Topic: To Catch a Thief (Read 3116 times) |
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brahms00
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To Catch a Thief
« on: Aug 21st, 2008, 12:16am » |
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Hi all. Here is the problem:
Person A (a good citizen in the original problem) is situated 100m north of the Person B (who is a thief)
Person B is moving to the East, while person A is moving towards B, always facing him. The speed of the person A is two times faster than person B (Speeds are constant).
How much distance is taken by the person A, when A catches B.
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Wardub
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Posts: 130
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Re: To Catch a Thief
« Reply #1 on: Aug 21st, 2008, 7:33am » |
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2  (10000/3) meters
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Grimbal
wu::riddles Moderator
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Re: To Catch a Thief
« Reply #2 on: Aug 21st, 2008, 9:13am » |
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That would be if A goes straight to the interception point.
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| « Last Edit: Aug 21st, 2008, 9:13am by Grimbal » |
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Wardub
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Re: To Catch a Thief
« Reply #3 on: Aug 21st, 2008, 9:25am » |
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on Aug 21st, 2008, 9:13am, Grimbal wrote:| That would be if A goes straight to the interception point. |
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Yep I just realized that. I tend to make problems easier than they really are.
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Eigenray
wu::riddles Moderator
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Re: To Catch a Thief
« Reply #4 on: Aug 22nd, 2008, 7:03am » |
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The case where they have the same velocity was considered here.
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