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wu :: forums    riddles    medium (Moderators: ThudnBlunder, Eigenray, SMQ, Grimbal, william wu, towr, Icarus)    n = (x+y+z)^2/(xyz) « Previous topic | Next topic » Pages: 1  Reply Notify of replies Send Topic Print    Author  Topic: n = (x+y+z)^2/(xyz)  (Read 661 times) wonderful Full Member     Posts: 203 n = (x+y+z)^2/(xyz)   « on: Jun 23rd, 2008, 2:48pm » Quote Modify Find all natural number(s) n  satisfying the above equation given x, y, z are natural.   Have A Great Day! IP Logged Eigenray wu::riddles Moderator Uberpuzzler     Gender: Posts: 1948 Re: n = (x+y+z)^2/(xyz)   « Reply #1 on: Jun 27th, 2008, 6:33pm » Quote Modify Nobody?  The solution is much like the solution to the problem this problem is much like. IP Logged wonderful Full Member     Posts: 203 Re: n = (x+y+z)^2/(xyz)   « Reply #2 on: Jun 29th, 2008, 8:33pm » Quote Modify Yes, this question  can be solved using a method very similar to Eigenray's solution.  Hint: (x, y, z) is a solution then (x, y, (x+y)^2/z) is also.   Have A Great Day! IP Logged Pages: 1  Reply Notify of replies Send Topic Print Forum Jump: ----------------------------- riddles -----------------------------  - easy => medium   - hard   - what am i   - what happened   - microsoft   - cs   - putnam exam (pure math)   - suggestions, help, and FAQ   - general problem-solving / chatting / whatever ----------------------------- general -----------------------------  - guestbook   - truth   - complex analysis   - wanted   - psychology   - chinese « Previous topic | Next topic »

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