Author |
Topic: Orthogonal Views (Read 6999 times) |
|
william wu
wu::riddles Administrator
Gender:
Posts: 1291
|
See the picture below. This cute puzzle has the nice properties of (1) being accessible to anyone (e.g., 4 year olds), and (2) initially appearing to be impossible. So it will drive you crazy until you figure it out
|
« Last Edit: May 17th, 2008, 4:34am by william wu » |
IP Logged |
[ wu ] : http://wuriddles.com / http://forums.wuriddles.com
|
|
|
towr
wu::riddles Moderator Uberpuzzler
Some people are average, some are just mean.
Gender:
Posts: 13730
|
|
Re: Orthogonal Views
« Reply #1 on: May 17th, 2008, 4:25am » |
Quote Modify
|
The only thing I can make of it gives numerous possible solutions, so it doesn't really keep my interest enough to drive me crazy.
|
|
IP Logged |
Wikipedia, Google, Mathworld, Integer sequence DB
|
|
|
rmsgrey
Uberpuzzler
Gender:
Posts: 2873
|
|
Re: Orthogonal Views
« Reply #2 on: May 17th, 2008, 7:07am » |
Quote Modify
|
a smooth curve resembling y=-x^2 on [-3,3] with a chord across the bottom
|
|
IP Logged |
|
|
|
SMQ
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 2084
|
Similar to what rmsgrey said (zipped to hide answer) --SMQ
|
|
IP Logged |
--SMQ
|
|
|
FiBsTeR
Senior Riddler
Gender:
Posts: 581
|
I must be missing something; this is what I first thought of, and it still seems to fit the problem:
|
|
IP Logged |
|
|
|
Barukh
Uberpuzzler
Gender:
Posts: 2276
|
|
Re: Orthogonal Views
« Reply #5 on: May 17th, 2008, 10:23am » |
Quote Modify
|
on May 17th, 2008, 9:07am, SMQ wrote:Similar to what rmsgrey said (zipped to hide answer) |
| Cannot imagine how this solves the problem... Could you draw a stereometric view?
|
|
IP Logged |
|
|
|
Grimbal
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 7527
|
Is this what you had in mind?
|
|
IP Logged |
|
|
|
SMQ
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 2084
|
on May 17th, 2008, 10:23am, Barukh wrote:Could you draw a stereometric view? |
| Sure, stereometric and isometric both.
|
|
IP Logged |
--SMQ
|
|
|
Eigenray
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 1948
|
|
Re: Orthogonal Views
« Reply #8 on: May 17th, 2008, 10:38pm » |
Quote Modify
|
Now how about an anaglyph image?
|
|
IP Logged |
|
|
|
Grimbal
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 7527
|
Why so complicated?
|
|
IP Logged |
|
|
|
rmsgrey
Uberpuzzler
Gender:
Posts: 2873
|
|
Re: Orthogonal Views
« Reply #10 on: May 18th, 2008, 4:19am » |
Quote Modify
|
on May 17th, 2008, 10:01am, FiBsTeR wrote:I must be missing something; this is what I first thought of, and it still seems to fit the problem: |
| It has extra edges on, which would conventionally be drawn in a projection - as silhouettes, the side view has a lot of possibilities even without poking additional holes through. The curved solutions solve the problem of the missing edges, but Grimbal's solution is even better.
|
|
IP Logged |
|
|
|
SMQ
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 2084
|
on May 17th, 2008, 10:38pm, Eigenray wrote:Now how about an anaglyph image? |
| If that's what floats your boat. (left eye is cyan) --SMQ
|
|
IP Logged |
--SMQ
|
|
|
Barukh
Uberpuzzler
Gender:
Posts: 2276
|
|
Re: Orthogonal Views
« Reply #12 on: May 18th, 2008, 5:50am » |
Quote Modify
|
Awesome, SMQ! What software are you using?
|
|
IP Logged |
|
|
|
SMQ
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 2084
|
on May 18th, 2008, 5:50am, Barukh wrote:What software are you using? |
| Povray for the rendering, and since I'm not on my normal computer with Photoshop at the moment, a quickie BASIC program to combine the anaglyph images and MS Paint for cropping and PNG conversion. I've attached the Povray source for anyone interested. --SMQ
|
|
IP Logged |
--SMQ
|
|
|
Eigenray
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 1948
|
|
Re: Orthogonal Views
« Reply #14 on: May 18th, 2008, 9:55am » |
Quote Modify
|
Awesome. Now do Magic Eye!
|
|
IP Logged |
|
|
|
SMQ
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 2084
|
You just don't give up, do you? --SMQ
|
|
IP Logged |
--SMQ
|
|
|
Eigenray
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 1948
|
|
Re: Orthogonal Views
« Reply #16 on: May 18th, 2008, 1:13pm » |
Quote Modify
|
Impressive! How about an animated anaglyph/autostereogram of it rotating?
|
« Last Edit: May 18th, 2008, 1:14pm by Eigenray » |
IP Logged |
|
|
|
towr
wu::riddles Moderator Uberpuzzler
Some people are average, some are just mean.
Gender:
Posts: 13730
|
|
Re: Orthogonal Views
« Reply #18 on: May 19th, 2008, 1:57am » |
Quote Modify
|
on May 19th, 2008, 1:33am, william wu wrote:These answers, while perfectly legit, are a lot more complicated than I expected ... |
| I don't think your solution works; if you cut a piece out of a cylinder at the height required by the front view (with the right width), you won't get a square as required in the top view..
|
|
IP Logged |
Wikipedia, Google, Mathworld, Integer sequence DB
|
|
|
JohanC
Senior Riddler
Posts: 460
|
|
Re: Orthogonal Views
« Reply #19 on: May 19th, 2008, 2:18am » |
Quote Modify
|
on May 19th, 2008, 1:57am, towr wrote: I don't think your solution works; if you cut a piece out of a cylinder at the height required by the front view (with the right width), you won't get a square as required in the top view.. |
| Maybe an elliptical cylinder would work?
|
|
IP Logged |
|
|
|
towr
wu::riddles Moderator Uberpuzzler
Some people are average, some are just mean.
Gender:
Posts: 13730
|
|
Re: Orthogonal Views
« Reply #20 on: May 19th, 2008, 2:42am » |
Quote Modify
|
on May 19th, 2008, 2:18am, JohanC wrote:Maybe an elliptical cylinder would work? |
| Then the top view wouldn't be a square.
|
|
IP Logged |
Wikipedia, Google, Mathworld, Integer sequence DB
|
|
|
william wu
wu::riddles Administrator
Gender:
Posts: 1291
|
Hmm, fair enough ... but, perhaps we can just slice the cylinder in half, lengthwise, to get the front view.
|
« Last Edit: May 19th, 2008, 12:39pm by william wu » |
IP Logged |
[ wu ] : http://wuriddles.com / http://forums.wuriddles.com
|
|
|
SMQ
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 2084
|
Sorry, William, still won't work. If, in the side view, you drew an isosceles triangle from the bottom corners to the top center it would pass exactly through the needed width of the top cut out (see diagram). So any profile which is the same height, is convex on top, and passes through those same points must have some concave portions somewhere along its length. No profile without at least one inflection point (on each side) can satisfy all the constraints of the given problem. --SMQ
|
« Last Edit: May 19th, 2008, 12:54pm by SMQ » |
IP Logged |
--SMQ
|
|
|
Sir Col
Uberpuzzler
impudens simia et macrologus profundus fabulae
Gender:
Posts: 1825
|
When I went to school woodwork, metal work, and technical drawing lessons were compulsory for boys and I loved these types of puzzle. I used to give them to my students when I first started teaching, but it seems that over the years they've become a lost art. Here are two of my fiendishly hard favourites. Puzzle B is a variation of Williams, so it isn't really a challenge now you've seen his answer. However, puzzle A is still a nice one to have a stab at.
|
|
IP Logged |
mathschallenge.net / projecteuler.net
|
|
|
SMQ
wu::riddles Moderator Uberpuzzler
Gender:
Posts: 2084
|
I, too, am glad I had the chance to take technical drawing. On the other hand, I helped to set up the CAD lab at my high school, so I guess I'm partly responsible for the demise of the art... Zipped solution to A attached. (And I notice you altered your diagram of B to better fit the "intended" solution. ) --SMQ
|
|
IP Logged |
--SMQ
|
|
|
|