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Topic: Proof (?) of Fermat's Last Theorem (Read 676 times) |
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cool_joh
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Proof (?) of Fermat's Last Theorem
« on: Dec 19th, 2007, 7:39pm » |
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an+bn=cn an-0n=cn-bn n=3, sequence of power: 0, 1, 8, 27, 64, 125 n=4, seq: 0, 1, 16, 81, 256... and so on. Note that the difference goes larger as the sequence goes higher. So it's impossible that there are two pairs of terms which has the same differences. Sorry about my poor English, I hope you understand. But, I doubt that this really prove the theorem. Can anyone find any mistakes? ---inspired by nick
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Obob
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Re: Proof (?) of Fermat's Last Theorem
« Reply #1 on: Dec 19th, 2007, 9:33pm » |
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The logic just plain doesn't work, is what the error is. By the exact same argument, a2+b2=c2 shouldn't have any solutions either, which is absurd. There is no obvious reason why the difference of two terms in the n=4 sequence shouldn't again be in the n=4 sequence, for instance.
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Hippo
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Re: Proof (?) of Fermat's Last Theorem
« Reply #2 on: Dec 20th, 2007, 4:17am » |
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on Dec 19th, 2007, 7:39pm, cool_joh wrote:an+bn=cn an-0n=cn-bn n=3, sequence of power: 0, 1, 8, 27, 64, 125 n=4, seq: 0, 1, 16, 81, 256... and so on. Note that the difference goes larger as the sequence goes higher. So it's impossible that there are two pairs of terms which has the same differences. Sorry about my poor English, I hope you understand. But, I doubt that this really prove the theorem. Can anyone find any mistakes? ---inspired by nick |
| Noone talks about differences of neighbouring members. ...
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SMQ
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Re: Proof (?) of Fermat's Last Theorem
« Reply #3 on: Dec 20th, 2007, 5:42am » |
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on Dec 19th, 2007, 7:39pm, cool_joh wrote:Note that the difference goes larger as the sequence goes higher. So it's impossible that there are two pairs of terms which has the same differences. |
| But that's just as true of the sequence of squares: 0, 1, 4, 9, 16, 25, ... yet 9 + 16 = 25 (and those are even adjacent terms!). --SMQ
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--SMQ
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Grimbal
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Re: Proof (?) of Fermat's Last Theorem
« Reply #4 on: Dec 20th, 2007, 6:35am » |
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It also happens that 123-93 = 103-13
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FiBsTeR
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Re: Proof (?) of Fermat's Last Theorem
« Reply #5 on: Dec 20th, 2007, 5:11pm » |
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on Dec 20th, 2007, 6:35am, Grimbal wrote:It also happens that 123-93 = 103-13 |
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