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   Author  Topic: Solvng in Radicals  (Read 591 times)
Barukh
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Solvng in Radicals  
« on: Nov 19th, 2007, 10:04am »		 Quote Quote Modify Modify
Solve in radicals:
 
(5-x) = x2 - 5.
 
Edited (fixed a typo).
« Last Edit: Nov 19th, 2007, 10:50am by Barukh » IP Logged
Joe Fendel
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Re: Solvng in Radicals  
« Reply #1 on: Nov 19th, 2007, 11:46am »		 Quote Quote Modify Modify
Okay, I'll try this one:
 
hidden:
Square both sides to get
5 - x = x4 - 10x2 + 25

so we're solving for x4 - 10x2 + x + 20 = 0.  This factors into
(x2 - x - 4)(x2 + x - 5) = 0

Therefore the solutions can be obtained by the quadratic formula:
 
x = one of the following:
a) (1 + 17)/2  
b) (1 - 17)/2  
c) (-1 + 21)/2  
d) (-1 - 21)/2  
« Last Edit: Nov 19th, 2007, 11:46am by Joe Fendel » IP Logged
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