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   Author  Topic: Combination  (Read 519 times)
mikedagr8
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Combination  
« on: Oct 17th, 2007, 12:28am »
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Find 9 different integers from 1-20 inclusive such that no combination of any 3 of the 9 form an arithmetic progression. For example, if 2 integers chosen were 7 and 13, then that would preclude 1,10, and 19 from being included.
« Last Edit: Oct 17th, 2007, 4:28am by mikedagr8 » IP Logged

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Re: Combination  
« Reply #1 on: Oct 17th, 2007, 1:56am »
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I have found out 8 integers that satisfy the condition. They are 1,2,4,5,10,11,13 and 14. I am still working on the ninth.
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mikedagr8
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Re: Combination  
« Reply #2 on: Oct 17th, 2007, 4:30am »
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on Oct 17th, 2007, 1:20am, Grimbal wrote:
You meant 7 and 13?

I did.  
 
I have seen this done in two ways. I was able to solve it for only one of them.
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Re: Combination  
« Reply #3 on: Oct 17th, 2007, 6:58am »
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If you know one solution, the other is easy to find.
bi = 21 - ai
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mikedagr8
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Re: Combination  
« Reply #4 on: Oct 17th, 2007, 2:28pm »
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What does that mean Huh
I'm guessing you either know both answers, or still working it out. Lips Sealed
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Re: Combination  
« Reply #5 on: Oct 17th, 2007, 2:53pm »
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He means that if you had one solution, then you could take each number and subtract them from 21 (essentially "reversing" the list starting at 20 and counting down), and you would end up with another solution.
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Grimbal
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Re: Combination  
« Reply #6 on: Oct 17th, 2007, 2:59pm »
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If you have one solution, say
1, 2, 4, 5, 10, 11, 13, 14
You can get a solution by taking it backwards, taking 21-x for each element x.
20, 19, 17, 16, 11, 10, 8, 7
Which is another solution for 6.
Obviously, a, b, c are in a linear progression if and only if 21-a, 21-b, 21-c are.
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Re: Combination  
« Reply #7 on: Oct 17th, 2007, 3:16pm »
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Well, I have found the solutions - by complete enumeration, by lack of better alternatives that are apparent to me. (I tried to do it by hand, and found the same solution gotit mentioned for 8 numbers; but I couldn't get any further.)
 
hidden:
We have as the only solutions
 
1, 2, 6, 7, 9, 14, 15, 18, 20
 
and its complement, as Grimbal noted,
 
20, 19, 15, 14, 12, 7, 6, 3, 1.

 
Edit: if someone finds a neater way to do this, I'm very interested...
« Last Edit: Oct 17th, 2007, 3:17pm by pex » IP Logged
mikedagr8
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Re: Combination  
« Reply #8 on: Oct 18th, 2007, 1:44am »
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Those are the answers I had. I found mine by hand over the course of 2 gruelling hours Undecided.
« Last Edit: Oct 18th, 2007, 1:45am by mikedagr8 » IP Logged

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Grimbal
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Re: Combination  
« Reply #9 on: Oct 18th, 2007, 2:48am »
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My computer found them by hand over the course of 40 gruelling milliseconds.  Grin
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mikedagr8
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Re: Combination  
« Reply #10 on: Oct 18th, 2007, 2:51am »
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on Oct 18th, 2007, 2:48am, Grimbal wrote:
My computer found them by hand over the course of 40 gruelling milliseconds.  Grin

You're computer is obviously programmed a lot better than my 13 year old mine at the time  Tongue. Also I can only do one search at a time, not many thousands (I assume).
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