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   A Prime Number And Power Puzzle
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   Author  Topic: A Prime Number And Power Puzzle  (Read 266 times)
K Sengupta
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A Prime Number And Power Puzzle  
« on: Jul 13th, 2007, 9:48am »
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A is a prime number while B and C are positive integers with B  not equal to 11 and C>=2.
 
Analytically determine all possible solutions to this equation:
 
2A + 3A= 11*BC
« Last Edit: Jul 13th, 2007, 10:04am by K Sengupta » IP Logged
SMQ
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Re: A Prime Number And Power Puzzle  
« Reply #1 on: Jul 13th, 2007, 10:15am »
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2A + 3A = 0 (mod 11) implies A = 5(2N+1) for some integer N, therefore A prime implies A = 5.
 
Thus 25 + 35 = 275 = 11*25 implies BC = 25.  Therefore B = 5 and C = 2.
 
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Archae
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Re: A Prime Number And Power Puzzle  
« Reply #2 on: Jul 13th, 2007, 1:21pm »
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How do you know that 2^A + 3^A = 0 (mod 11) implies that A = 5(2N+1)?  Am I being oblivious and missing something?  Thanks in advance for the explanation.
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Re: A Prime Number And Power Puzzle  
« Reply #3 on: Jul 13th, 2007, 1:43pm »
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A |2A (mod 11) |3A (mod 11) |2A+3A (mod 11)
----+------------+------------+----------------
0 |1 |1 |2
1 |2 |3 |5
2 |4 |9 |2
3 |8 |5 |2
4 |5 |4 |9
5 |10 |1 |0
6 |9 |3 |1
7 |7 |9 |5
8 |3 |5 |8
9 |6 |4 |10
10 |1 |1 |2

 
So the pattern repeats every 10, and the only A's with a sum of 0 (mod 11) are A = 5 (mod 10).
 
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Re: A Prime Number And Power Puzzle  
« Reply #4 on: Jul 15th, 2007, 10:13pm »
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Thanks, SMQ.  I wasn't as rigorous as I should have been before asking the question.  
Now I know.
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