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Topic: A Prime Number And Power Puzzle (Read 266 times) |
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K Sengupta
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A Prime Number And Power Puzzle
« on: Jul 13th, 2007, 9:48am » |
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A is a prime number while B and C are positive integers with B not equal to 11 and C>=2. Analytically determine all possible solutions to this equation: 2A + 3A= 11*BC
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« Last Edit: Jul 13th, 2007, 10:04am by K Sengupta » |
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SMQ
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Re: A Prime Number And Power Puzzle
« Reply #1 on: Jul 13th, 2007, 10:15am » |
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2A + 3A = 0 (mod 11) implies A = 5(2N+1) for some integer N, therefore A prime implies A = 5. Thus 25 + 35 = 275 = 11*25 implies BC = 25. Therefore B = 5 and C = 2. --SMQ
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Archae
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Re: A Prime Number And Power Puzzle
« Reply #2 on: Jul 13th, 2007, 1:21pm » |
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How do you know that 2^A + 3^A = 0 (mod 11) implies that A = 5(2N+1)? Am I being oblivious and missing something? Thanks in advance for the explanation.
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SMQ
wu::riddles Moderator Uberpuzzler
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Re: A Prime Number And Power Puzzle
« Reply #3 on: Jul 13th, 2007, 1:43pm » |
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A | | | 2A (mod 11) | | | 3A (mod 11) | | | 2A+3A (mod 11) | ---- | + | ------------ | + | ------------ | + | ---------------- | 0 | | | 1 | | | 1 | | | 2 | 1 | | | 2 | | | 3 | | | 5 | 2 | | | 4 | | | 9 | | | 2 | 3 | | | 8 | | | 5 | | | 2 | 4 | | | 5 | | | 4 | | | 9 | 5 | | | 10 | | | 1 | | | 0 | 6 | | | 9 | | | 3 | | | 1 | 7 | | | 7 | | | 9 | | | 5 | 8 | | | 3 | | | 5 | | | 8 | 9 | | | 6 | | | 4 | | | 10 | 10 | | | 1 | | | 1 | | | 2 | So the pattern repeats every 10, and the only A's with a sum of 0 (mod 11) are A = 5 (mod 10). --SMQ
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Archae
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Re: A Prime Number And Power Puzzle
« Reply #4 on: Jul 15th, 2007, 10:13pm » |
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Thanks, SMQ. I wasn't as rigorous as I should have been before asking the question. Now I know.
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