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   Certain Composite Catalans
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   Author  Topic: Certain Composite Catalans  (Read 397 times)
Aryabhatta
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Certain Composite Catalans  
« on: Jun 13th, 2007, 6:38pm »
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If n = 3 (mod 6),  
 
prove/disprove:
 
The nth Catalan number, C(2n,n)/(n+1), is divisible by n+2.
 
(C(n,k) = n choose k, number of ways of selecting k objects from n objects)
« Last Edit: Jun 13th, 2007, 6:44pm by Aryabhatta » IP Logged
Aryabhatta
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Re: Certain Composite Catalans  
« Reply #1 on: Jun 20th, 2007, 3:04pm »
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Before I forget...
 
I think we can prove it, using the below repeatedly
 

i) if (a,b) = 1 and if ax and bx are both integers, then x is an integer.
 
ii) if N +1 = a + b and (a,b) = 1 then N! is divisible by a! * b! (follows from i)
« Last Edit: Jun 20th, 2007, 3:04pm by Aryabhatta » IP Logged
Eigenray
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Re: Certain Composite Catalans  
« Reply #2 on: Jun 20th, 2007, 9:34pm »
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It helps to first show that Cn = C(2n,n)/(n+1) is an integer:
hidden:
(2n+1)C(2n,n) = (n+1)C(2n+1,n), and since n+1, 2n+1 are relatively prime, n+1 divides C(2n,n).
 
Similarly, (2n+2)(2n+1)Cn = (n+2)C(2n+2,n), so n+2 divides Cn if n+2 is relatively prime to 2n+1 and 2n+2.  (n+2, 2n+2) = (n+2, 2) = 1 iff n is odd, and (n+2, 2n+1) = (n+2, 3) = 1 iff n is either 0 or 2 mod 3.  So n+2 | Cn whenever n is 3 or 5 mod 6.
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Aryabhatta
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Re: Certain Composite Catalans  
« Reply #3 on: Jun 21st, 2007, 10:20am »
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Nice!
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